Projectile Motion Question: Solving for Height of Pier Above Water

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SUMMARY

The problem involves calculating the height of a pier from which a swimmer dives, using projectile motion equations. The swimmer's horizontal velocity is 1.80 m/s, and the horizontal distance to the water is 0.80 m. By applying the formula Vx = change X / change Time, the time of flight was determined to be 0.44 seconds. Subsequently, using the formula change Y = Vyi * change Time + 1/2 * a * (change time)^2, the height of the pier was calculated to be 0.94 meters.

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[SOLVED] Projectile Motion Question

Homework Statement



a swimmer moving at 1.80m/s dives off a pier and hits the water .80 m from the edge of the pier how high is the pier above the water

Homework Equations


Vx=change X /change Time
change Y = Vyi . change Time +1/2 a . (change time)^2

The Attempt at a Solution



i found time with the Vx formula to be .44m/s
then i punched it into the change Y formula to get the height of the pier as 0.94 m

im just wondering if i approached it right and by change i mean the displacement triangle i just don't know how to make the symbol sorry

thanks ahead of time
 
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Looks good, but don't round any of your answers until you get your final answer and your time is supposed to be in units of s, not m/s.
 
woops a typo there and i didnt round on paper i just wanted to make sure i had it right thanks a lot !
 

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