- #1

lightarrow

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Let's consider the position x and momentum p of a free particle.

[tex]\Delta\ x\Delta\ p\geq \hbar/2[/tex] so, if [tex]\Delta \ x[/tex] is little enough, [tex]\Delta \ p[/tex] is big enough.

The fact [tex]\Delta \ p[/tex] is big implies that we cannot say the momentum conservation law is valid anylonger.

But:

space is homogeneus --> momentum conservation,

non conservation of momentum --> space is not homogeneus

So, for [tex]\Delta \ x[/tex] very little, that is, considering space at very small distances, space itself must be non-homogeneus.

Consider that this is a very rough reasoning with no pretence at all.

Can it have any meaning?

[tex]\Delta\ x\Delta\ p\geq \hbar/2[/tex] so, if [tex]\Delta \ x[/tex] is little enough, [tex]\Delta \ p[/tex] is big enough.

The fact [tex]\Delta \ p[/tex] is big implies that we cannot say the momentum conservation law is valid anylonger.

But:

space is homogeneus --> momentum conservation,

non conservation of momentum --> space is not homogeneus

So, for [tex]\Delta \ x[/tex] very little, that is, considering space at very small distances, space itself must be non-homogeneus.

Consider that this is a very rough reasoning with no pretence at all.

Can it have any meaning?

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