Helmholtz resonator equation. How do I do this? Please help.

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    Helmholtz Resonator
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Discussion Overview

The discussion revolves around the Helmholtz resonator equation, focusing on how to solve for the area (A) given various parameters such as volume (Vo), frequency (F), and the speed of sound (V). Participants express confusion regarding the proper use of units, particularly whether volume should be cubed and how to handle the dimensions in the equation.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant questions whether the volume (Vo) should be cubed, given that it is expressed in cubic centimeters.
  • Another participant asserts that L cannot be zero, as it would invalidate the equation.
  • There is a debate about the proper treatment of units, with some participants emphasizing the need to maintain consistent units throughout the calculations.
  • Several participants express confusion about the algebraic manipulation of the equation and the order of operations required to isolate A.
  • One participant suggests that the speed of sound must be converted to match the units used for the resonator, specifically centimeters.
  • Another participant provides a step-by-step algebraic approach to rearranging the equation to solve for A, emphasizing the importance of inserting numerical values only at the final step.
  • Concerns are raised about the clarity of earlier posts, with some participants finding them incomprehensible or lacking in mathematical rigor.

Areas of Agreement / Disagreement

Participants generally express disagreement on several points, particularly regarding the treatment of units and the validity of certain assumptions in the equation. There is no consensus on how to proceed with the calculations or the interpretation of the parameters involved.

Contextual Notes

Participants highlight limitations in understanding the mathematical steps and the implications of using different units. There is uncertainty about how to correctly apply the Helmholtz resonator equation given the various interpretations of the parameters.

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Helmholtz resonator equation. How do I do this?? Please help.

helmholtz.JPG


L = 0
Vo = 473.17 (I think its cubed though I calculated it from 16 ounces, so I should be cubed right??)
A = What I am solving for
F = 480 hz
V= speed of sound which is 340.19 at sea level

If Vo needs to be cubed then A should be squared, but I don't know if I am supposed to do that

Ive put all this down on paper and I am not sure how to run this equation to solve especially when it comes to the square root of a fraction, especially if the fraction is cubed and squared.

How do I do this? Been searching the internet for 2 days now trying to figure this out.
 
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What do you mean by cubed or squared??
You have a formula.
Solve it for A.

L cannot be 0, do you understand why?
 
Yes because then the it would be multiplied by Vo and would end in zero. By zero I me L is non existent in the equation, there is no neck to the helmholtz resonator. So L needs to be left out.

By cubed and squared I mean that it asked for Volume, the volume is 473.17 cubic centimeters. So it should be cubed right?? Really stupid question but I just want to make sure that's the case
 
I'm sorry.
What you write is completely incomprehensible.
It doesn't seem that you even know what the number 0 is, nor what an equation is, either.
 
arildno said:
I'm sorry.
What you write is completely incomprehensible.
It doesn't seem that you even know what the number 0 is, nor what an equation is, either.

uh its very comprehensible.
 
No, it is not
1. You can't put 0 in the denominator of an expression.
2. Volume cubed?? The volume stands there without any cubing done at all.
3. Why should you square A? You are to solve for it.
 
arildno said:
No, it is not
1. You can't put 0 in the denominator of an expression.
2. Volume cubed?? The volume stands there without any cubing done at all.
3. Why should you square A? You are to solve for it.

L is now .028448 centimeters. I guess you have to account for the thickness of the metal.

It what sense does the volume sit there without any cubing? Its 473.17 cubic centimeters. So, wouldn't you put in the equation as 473.17^3?

The result of A should be equal to centimeters squared correct? Thats just one other thing I am unsure of. Is that I took the volume and converted it from ounces to cubic centimeters, so how should I input it into the equation?
 
"Its 473.17 cubic centimeters. So, wouldn't you put in the equation as 473.17^3?2
Why?
You have 473.17 cubic centimeters, not 473.17^3 cubic centimeters.

A cubic centimeter is a unit for volume counting.
 
arildno said:
"Its 473.17 cubic centimeters. So, wouldn't you put in the equation as 473.17^3?2
Why?
You have 473.17 cubic centimeters, not 473.17^3 cubic centimeters.

A cubic centimeter is a unit for volume counting.

Ok I understand then, that is what I was unsure of.

Let me try again to see if I can run this equation
 
  • #10
Run an equation?
Shouldn't you solve it for A??
 
  • #11
2wqvdxe.jpg


Thats where I got to, now what? and is it correct?
 
  • #12
arildno said:
Run an equation?
Shouldn't you solve it for A??

thats what I meant by run it?
 
  • #13
Here's how you may do it:
1. NEVER insert numbers until your last step, solve it algebraically!
2. We have:
f_{H}=\frac{v}{2\pi}\sqrt{\frac{A}{V_{0}L}}
We multiply with 2pi/v, gaining:
\sqrt{\frac{A}{V_{0}L}}=\frac{2\pi{f}_{H}}{v}
We square both sides,
\frac{A}{V_{0}L}=\frac{4\pi^{2}{f}^{2}_{H}}{v^{2}}
We multiply with V_{0}L, and gain:
A=V_{0}L\frac{4\pi^{2}{f}^{2}_{H}}{v^{2}}
3. NOW, insert numbers to calculate A!
 
  • #14
arildno said:
3. NOW, insert numbers to calculate A!
If I may add: with units, otherwise you are in for a bad surprise.
 
  • #15
arildno said:
Here's how you may do it:
1. NEVER insert numbers until your last step, solve it algebraically!
2. We have:
f_{H}=\frac{v}{2\pi}\sqrt{\frac{A}{V_{0}L}}
We multiply with 2pi/v, gaining:
\sqrt{\frac{A}{V_{0}L}}=\frac{2\pi{f}_{H}}{v}
We square both sides,
\frac{A}{V_{0}L}=\frac{4\pi^{2}{f}^{2}_{H}}{v^{2}}
We multiply with V_{0}L, and gain:
A=V_{0}L\frac{4\pi^{2}{f}^{2}_{H}}{v^{2}}
3. NOW, insert numbers to calculate A!

Thank you!
 
  • #16
DrClaude said:
If I may add: with units, otherwise you are in for a bad surprise.

Har har har. Sorry I am not a pro with math.
 
  • #17
If you just plug in the numbers, as you did in post #11, you will get the wrong answer because your units won't match.
 
  • #18
Ok I did 240 hertz instead, so an octave lower, and got 1033.4 that looks a bit better.
 
  • #19
So basically if what I have come up with is 9cm will give 120herts and 4.5 will give 60hertz.
 
  • #20
Just to be sure, the speed of sound need to be converted to the same units that I am using for the resonator correct? In this case, centimeters
 
  • #21
Well, to get the simplest correct expression, you should use the SAME scales for the same type of units.

For example, 10 meters divided by 20 centimeters equals 10m/(20cm)=0.5 m/(cm).

A rather simpler expression is to remember that 1 meter=100 cm, so that 0.5 m(cm)=0.5*100(cm)/(cm)=50
 

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