Help a Physics Student with Two Dim. Oscilator Problem

  • Context: Graduate 
  • Thread starter Thread starter noamriemer
  • Start date Start date
  • Tags Tags
    Oscilator
Click For Summary

Discussion Overview

The discussion revolves around a physics problem involving a two-dimensional oscillator described by a Hamiltonian. Participants are exploring the transformation of coordinates to eliminate linked terms in the Hamiltonian and clarifying the meaning of certain notation used in quantum mechanics.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification

Main Points Raised

  • One participant presents a Hamiltonian and seeks a transformation to remove the xy coupling term, proposing a new coordinate system with variables a and b.
  • Another participant suggests that the goal is to separate the equation into two independent equations, indicating that the transformation is on the right track.
  • A question arises regarding the notation |u_j⟩, with one participant speculating that it does not refer to the coordinates.
  • A later reply explains the meaning of |x⟩ as a localized state in quantum mechanics, describing it as a particle with a precise position but undefined momentum.

Areas of Agreement / Disagreement

Participants generally agree on the need to transform the Hamiltonian to eliminate the coupling term, but there is uncertainty regarding the interpretation of the notation used in the context of the Hamiltonian and quantum states.

Contextual Notes

There are unresolved aspects regarding the specific form of the transition matrix and the implications of the notation used, which may depend on the definitions and context of the problem.

Who May Find This Useful

Students and enthusiasts of physics, particularly those interested in Hamiltonian mechanics and quantum mechanics, may find this discussion relevant.

noamriemer
Messages
50
Reaction score
0
Hello! I am new here...
I am a physics student, seeking for help. There is something I just can't seem to understand...
Your help will be much appreciated...

In my exercise, I have the following Hamiltonian:
H=\frac{p_x^2}{2m}+\frac{p_y^2}{2m}+\frac{1}{2}m \omega^2 (x^2+y^2)+\lambda xy

I was supposed to find a transformation for which there will be no "linked" coordinates. This is what I came up with:
H=\frac{p_a^2}{2m}+\frac{p_b^2}{2m}+\frac{a^2}{2}(m\omega^2+\lambda)+\frac{b^2}{2}(m\omega^2-\lambda)

I need to find the transition matrix. And here I am facing my problems:
The matrix is given by:
H=\left \langle u_i|H|u_j \right \rangle= \left \langle u_i|v_j \right \rangle\left \langle v_j|H|v_l \right \rangle\left \langle v_l \right |u_j\rangle

But I can't understand... what are the u_j ?
Does it refer to the coordinates- so in my case it will be:
H=\left \langle x|H|y \right \rangle= \left \langle x|b \right \rangle\left \langle b|H|a \right \rangle\left \langle a \right |y\rangle

If it is so: what does |x\rangle mean?

Thank you all so much!
 
Last edited:
Physics news on Phys.org
In the first part you need to add and subtract terms such that there is no x*y term, or in other words, the equation can be separated into two independent equations, each dependent on only one co-ordinate.
So if you can write the equation in a new co-ordinate system a and b, like you have, then yes, it is what is required as it can be separated into two independent equations.

As for the second part, I am not a 100% about this, but ui and uj should not be the co-ordinates.
 
noamriemer said:
If it is so: what does |x\rangle mean?

This is a purely localized state. A particle (wavefunction) that has an exact, 100% accurate position, but totally undefined momentum. You can imagine it as a delta function with a peak at position x. I like to think that it's the image of a drop just hitting the surface of water.
 
Thank you, guys... you've been great help!
 

Similar threads

  • · Replies 29 ·
Replies
29
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 31 ·
2
Replies
31
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 14 ·
Replies
14
Views
6K