Help finding the midpoint of a closed interval & more

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SUMMARY

This discussion focuses on finding the midpoint of a closed interval [a,b] and understanding the significance of the parameter t in the context of linear interpolation. The key points include proving that for any x in [0,b], x can be expressed as x=tb for some t in [0,1], with the midpoint being b/2. Additionally, for the interval [a,b], x can be represented as x=(1-t)a+tb, where the midpoint is (a+b)/2. The discussion emphasizes the importance of specific values of t to determine points within the interval.

PREREQUISITES
  • Understanding of closed intervals in mathematics
  • Basic knowledge of linear interpolation
  • Familiarity with the concept of midpoints
  • Elementary algebra and calculus concepts
NEXT STEPS
  • Study the properties of closed intervals in real analysis
  • Learn about linear interpolation and its applications
  • Explore the concept of midpoints in various mathematical contexts
  • Investigate the significance of parameterization in calculus
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Students revisiting calculus concepts, educators teaching linear interpolation, and anyone interested in the mathematical properties of intervals and midpoints.

Queens
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Hey everyone,

This is a review of some stuff I learned in high school, but I haven't actually done anything calculus related in about 2 years, and to be honest it looks foreign to me, if someone could help jog the old noodle it would help tremendously.

The first question is as follows;

1. There is a useful way of describing the points of the closed interval [a,b], as usual we assume that a<b.

a)Consider the interval [0,b], for b>0. Prove that if x lies in [0,b], then we have x=tb for some t with 0≤t≤1. What is the significance of the number t? What is the midpoint of the interval [0,b]?

b) Prove that if x ∈ [a,b], then we have x = (1-t)a+tb for some t with 0≤t≤1. What
is the midpoint of the interval [a,b]? What is the point 1/3 of the way from a to b?

c) Prove conversely that if 0≤t≤1 then (1-t)a+tb is in [a,b].



I have given this problem much though, and even asked some engineer buddies but the answer seems to elude all of us, perhaps t=inverse of b and the significance of that is... something.

I'm really grabbing at all I can get here, if anyone could help explain this to me I would appreciate it.

Thanks so much
 
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Queens said:
Hey everyone,

This is a review of some stuff I learned in high school, but I haven't actually done anything calculus related in about 2 years, and to be honest it looks foreign to me, if someone could help jog the old noodle it would help tremendously.

The first question is as follows;

1. There is a useful way of describing the points of the closed interval [a,b], as usual we assume that a<b.

a)Consider the interval [0,b], for b>0. Prove that if x lies in [0,b], then we have x=tb for some t with 0≤t≤1. What is the significance of the number t? What is the midpoint of the interval [0,b]?
t is just a number between 0 and 1 (inclusive). Try thinking about this with some concrete numbers. Suppose you're working with the interval [0, 1]. What's the midpoint of the interval?

Now suppose you're working with the interval [0, 5]. What's the midpoint now?

Can you make the leap to finding the midpoint of the interval [0, b]?
Queens said:
b) Prove that if x ∈ [a,b], then we have x = (1-t)a+tb for some t with 0≤t≤1. What
is the midpoint of the interval [a,b]? What is the point 1/3 of the way from a to b?
Try this out with some specific numbers, say [3, 7]. Can you see why x = (1 - t)*3 + t*7 hits every point in [3, 7] for some value of t? If t = 0, which point in the interval do you get? If t = 1, what point do you get now?
Queens said:
c) Prove conversely that if 0≤t≤1 then (1-t)a+tb is in [a,b].



I have given this problem much though, and even asked some engineer buddies but the answer seems to elude all of us, perhaps t=inverse of b and the significance of that is... something.

I'm really grabbing at all I can get here, if anyone could help explain this to me I would appreciate it.

Thanks so much
 

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