Help Finding the sum of the cubed and odd 5 digit numbers

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SUMMARY

The discussion focuses on calculating the sum of the cubes of all odd five-digit numbers. A participant seeks assistance in finding a formula for the sum of cubes, specifically asking for the general formula for the sum of cubes up to a certain limit, such as \(\sum_{i=1}^{1000000}{i^3}\). The conversation emphasizes the need to adapt this formula to account for the odd five-digit constraint. The participants aim to derive a solution that can be applied to both smaller and larger sets of numbers.

PREREQUISITES
  • Understanding of mathematical summation notation
  • Familiarity with the properties of odd numbers
  • Knowledge of cubic functions and their calculations
  • Basic programming skills to implement the formula in a coding environment
NEXT STEPS
  • Research the formula for the sum of cubes: \(\sum_{i=1}^{n}{i^3} = \left(\frac{n(n+1)}{2}\right)^2\)
  • Learn how to filter and calculate sums for odd numbers within a specified range
  • Explore programming techniques for implementing mathematical formulas in Python or JavaScript
  • Investigate optimization methods for calculating large sums efficiently
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Mathematicians, computer science students, and anyone interested in algorithm development for mathematical computations.

Brookejewel
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PLEASE HELP! I am so stuck on this, working on it for days

Im trying to find the sum of the cubes of all the odd 5 digit numbers..


if you know a formula that works even with smaller numbers so i can try solving it also but i need the answer as well
 
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Hi Brookejewel! :smile:

Do you know a formula for all the cubes (up to a certain point). Let's disregard the fact that they have to be odd and have 5 digits.

Do you know a formula for

[tex]\sum_{i=1}^{1000000}{i^3}[/tex]

for example? Once you know this formula, we will modify it to suit your purposes!
 

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