Help I need the solution for these two

  • Thread starter Thread starter vincikai
  • Start date Start date
Click For Summary

Homework Help Overview

The discussion revolves around two physics problems involving collisions and momentum conservation. The first problem concerns an elastic and a completely inelastic collision between two balls of different masses. The second problem involves two individuals on skates who push off from each other using a spring, and the goal is to determine one person's mass based on their velocities after the release.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the principles of conservation of momentum and kinetic energy in elastic collisions, as well as the implications of a completely inelastic collision. Questions arise about the setup of the problems and the assumptions regarding friction and mass distribution in the second scenario.

Discussion Status

Some participants have provided guidance on the principles involved in solving the problems, emphasizing the need to consider both momentum and energy conservation for the elastic collision. Others are exploring the implications of the center of mass in the second problem, noting the relationship between the velocities of Al and Jo.

Contextual Notes

Participants are reminded that solutions are not provided, and the focus is on understanding the underlying concepts and reasoning through the problems. The discussion reflects a collaborative effort to clarify the physics involved without arriving at definitive answers.

vincikai
Messages
9
Reaction score
0
A 2.30-kg ball, moving to the right at a velocity of +1.29 m/s on a frictionless table, collides head-on with a stationary 6.50-kg ball. Find the final velocities of (a) the 2.30-kg ball and of (b) the 6.50-kg ball if the collision is elastic. (c) Find the final velocity of the two balls if the collision is completely inelastic.




Consult Concept Simulation 7.1 in preparation for this problem. Two friends, Al and Jo, have a combined mass of 169 kg. At an ice skating rink they stand close together on skates, at rest and facing each other, with a compressed spring between them. The spring is kept from pushing them apart, because they are holding each other. When they release their arms, Al moves off in one direction at a speed of 1.15 m/s, while Jo moves off in the opposite direction at a speed of 1.20 m/s. Assuming that friction is negligible, find Al's mass.
 
Physics news on Phys.org
We do not provide solutions here, we will however, guide you through the question if you are willing to put some effort in :smile:
 
vincikai said:
A 2.30-kg ball, moving to the right at a velocity of +1.29 m/s on a frictionless table, collides head-on with a stationary 6.50-kg ball. Find the final velocities of (a) the 2.30-kg ball and of (b) the 6.50-kg ball if the collision is elastic. (c) Find the final velocity of the two balls if the collision is completely inelastic.

(a) and (b)
An elastic collision is one where both momentum and kinetic energy are conserved. Then, to solve this use both equations:

[tex]m_{1}\vec{v_{1i}} + m_{2}\vec{v_{2i}} = m_{1}\vec{v_{1f}} + m_{2}\vec{v_{2f}}[/tex]

[tex]\frac{1}{2}m_{1}v_{1i}^{2} + \frac{1}{2}m_{2}v_{2i}^{2} = \frac{1}{2}m_{1}v_{1f}^{2} + \frac{1}{2}m_{2}v_{2f}^{2}[/tex]

(c)
A perfectly inelastic collision is one that two objects stick together during a collision. Only momentum is conserved, which becomes:

[tex]m_{1}\vec{v_{1i}} + m_{2}\vec{v_{2i}} = (m_{1} + m_{2} )\vec{v_{f}}[/tex]
 
vincikai said:
Consult Concept Simulation 7.1 in preparation for this problem. Two friends, Al and Jo, have a combined mass of 169 kg. At an ice skating rink they stand close together on skates, at rest and facing each other, with a compressed spring between them. The spring is kept from pushing them apart, because they are holding each other. When they release their arms, Al moves off in one direction at a speed of 1.15 m/s, while Jo moves off in the opposite direction at a speed of 1.20 m/s. Assuming that friction is negligible, find Al's mass.

Because there's no friction, the center of mass of the two is going to be motionless. This means their momenta are equal and opposite
 

Similar threads

  • · Replies 19 ·
Replies
19
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
20
Views
3K
  • · Replies 6 ·
Replies
6
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
6
Views
5K
  • · Replies 4 ·
Replies
4
Views
5K