Help! I need to find the speed of a conveyor to keep consistent gaps

[wesman]

the first conveyor is moving at 37.5 in/s with a gap of 2 in between 5.5 in cartons. The second conveyor needs to have a minimum gap of 11 in, how do i find the speed needed for the second conveyor. Please help.

 

[berkeman]

Welcome to PF.

Can you say more about how the cartons are transferred from one conveyor belt to the other? Is it with some sort of pusher mechanism? And how are you going to deal with the slipping/tilting/falling of the cartons being transferred to the faster conveyor belt?

 

[wesman]

there is a lug chain pushing the cartons at a constant speed at the start, they are then pushed into a conveyor belt that holds them on both sides which prevents falling. for this calculation slip can just be neglected. thank you.

 

[DaveC426913]

Caveat: I am butting in where I don't belong because I know nothing about this.

Isn't it a matter of (2+5.5) : (11+5.5) :: 37.5 : ?

That gives a ratio of 2.2:1, giving me a conveyor speed of 82.5in/s.

Don't take my word for it.

 

[wesman]

the second conveyor needs to have an increased speed to increase the gap between the cartons. i understand that logic however the outcome is what doesn't make sense to me. I could be wrong though so i appreciate your input.

 

[DaveC426913]

the second conveyor needs to have an increased speed to increase the gap between the cartons. i understand that logic however the outcome is what doesn't make sense to me. I could be wrong though so i appreciate your input.

Sorry, I corrected the numbers. (For some reason I read "16.5" instead of "37.5".)

 

[Baluncore]

the first conveyor is moving at 37.5 in/s with a gap of 2 in between 5.5 in cartons. The second conveyor needs to have a minimum gap of 11 in, how do i find the speed needed for the second conveyor.

First conveyor. 5.5” + 2” = 7.5” between item centres.
37.5” / 7.5” = 5 items per second.
Second conveyor. 5.5” + 11” = 16.5” between item centres.
16.5” * 5 = 82.5” per second.