Help in re-parameterizing the curve

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SUMMARY

The discussion focuses on re-parameterizing the curve defined by δ(t)=(2/3(√(L^2+9))cos(t),1/3(√(L^2+9))sin(t),L) to achieve arc-length parameterization. The speed of the curve is determined to be 1/3√(L^2+9)√(1+3sin^2(t)). To re-parameterize, one must compute the integral of ||ds/du|| from zero to t, derive the function h(t), find its inverse f(t), and then compose the original curve with f(t) to obtain the desired arc-length parameterization.

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sarah7
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Hi,

can someone help in re-parameterizing the curve

δ(t)=(2/3(√(L^2+9))cos(t),1/3(√(L^2+9))sin(t),L)

I found dδ/dt then I got the speed to be 1/3√(L^2+9)√(1+3sin^2(t))

L is just a constant z=L

I know how to re-parameterize curves to make them parameterized by arc-length when I get a constant speed but here the speed is in terms of t!

Thanks
 
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You should get the integral of ||ds/du|| from zero to t, then you find the function h(t). After this you should find the inverse of h(t), say it is the function f(t), then you find the composition of your original curve and f(t), the new curve is a curve that is parametrized by arc length.
 

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