Help me im in WAS and i need to know Delta V. .

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SUMMARY

The discussion focuses on calculating the delta-V required for a space shuttle to perform a de-orbit maneuver, specifically lowering its perigee from 210 miles to 60 miles. The formula established indicates that for every mile of altitude lost, the shuttle's velocity decreases by 2 feet per second (fps). Given the altitude change of 150 miles, the required change in velocity is calculated to be 300 fps. Participants emphasize the importance of understanding the delta-V concept in layman's terms for better comprehension.

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  • Understanding of delta-V in orbital mechanics
  • Basic knowledge of altitude and velocity relationships
  • Familiarity with the concept of perigee and apogee in orbits
  • Ability to perform simple calculations involving feet per second (fps)
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  • Learn about de-orbit maneuvers and their significance in space missions
  • Explore the effects of altitude changes on spacecraft velocity
  • Study the physics of re-entry and atmospheric drag on spacecraft
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davo
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help me please I am in WAS and i need to know Delta V. please please please.

ok i am curently in WAS(wa arowspace scolars) I am a bad speller but i could care less also I am new hear. i know what the formula for delta v is but i do not understand it. i am interested in learning but please putin into layman's terms. also hear is the Question. De-orbit maneuvers are usually done to lower the perigee of the orbit to 60 miles (or less). The Orbiter is captured and re-enters as it passes into the atmosphere at this altitude.

There is a change of 1 mile for every 2 feet per second (fps) change in velocity when you are below a 500-mile altitude above the Earth.

Determine the change in velocity (delta-V) that the Shuttle will need to make if it is at an altitude of 220 miles above the Earth at apogee and 210 miles above the Earth at perigee, and needs to drop the perigee to an altitude of 60 miles.
 
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Delta v in this context is simply the change in the velocity of the shuttle. That is the original velocity minus the final velocity.
 
Kurdt said:
Delta v in this context is simply the change in the velocity of the shuttle. That is the original velocity minus the final velocity.
ok so then (if i understand u) from what the question stated (for its speed) every time its decreasing a mile its travaling 2fps below a 500 mile altitude above the Earth? So then really their asking me: when is the shuttle going to reach a perigee of 60 miles and how meny mile's/fps? I will try and wok it out and see what i get.
 
So for every mile in altitude lost the velocity changes by 2fps. So if the altitude decreases by x miles then the change in velocity is 2x fps.
 
Kurdt said:
So for every mile in altitude lost the velocity changes by 2fps. So if the altitude decreases by x miles then the change in velocity is 2x fps.

thank u so much man i will try it out and if u could tell me if it is right i would apreciate it. i should have it done soon.
 
ok so i came up with:it needs to travel 792,000ft to reach the 60 mile marker, and decreases 150 miles. am i right? sorry it took 4 ever i seam to compliate things and think of them in a bigger perportion even though they really arnt.
 
If it decreases by 150 miles then the change in speed is going to be 300 fps. fps = feet per second.
 
What are your future plans? Perhaps you need to reevaluate the importance you put on proper communication skills.

I for one had a hard time getting past the incorrect spelling and grammar in your question.
 
Kurdt said:
If it decreases by 150 miles then the change in speed is going to be 300 fps. fps = feet per second.

ok thank you. You made it seem a hell of a lot easyer then what it looked like.
 

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