Ignoring the fact that the atmospheric friction would probably disintegrate it. I know that to achieve LEO takes around 10km/s delta v. But only 2km/s of that is to overcome the drag and gravity. So you could shoot at 2km/s, get to LEO altitude then it falls back down because it is not at orbital velocity or trajectory right? And I think that you need around 16km/s (10 to LEO plus 6 from LEO to moon) for a rocket to safely land on the moon from Earth. But is it less than 16 if you just want to shoot a bullet and hit the moon? Would it be 2 + 6 = 8km/s ?? Wouldn't it at least be less than the 11.2km/s escape velocity of the Earth since if you shot a bullet to the altitude of the moon (but not near the moon) it would eventually fall back to Earth, so you havent escaped the Earths gravity.