How Do You Solve \(\dot y(x) - 2y(x) = y^2(x)-3\) in Differential Equations?

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SUMMARY

The differential equation \(\dot y(x) - 2y(x) = y^2(x)-3\) can be solved by recognizing it as separable. The transformation to the form \(\frac{dy}{dx} = y^2 + 2y - 3\) allows for straightforward integration. The solution process involves separating variables and integrating both sides, leading to the general function \(y(x)\). This method effectively simplifies the problem and provides a clear path to the solution.

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  • Understanding of separable differential equations
  • Familiarity with Bernoulli differential equations
  • Basic integration techniques
  • Knowledge of function transformations
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  • Study the method of solving separable differential equations
  • Learn about Bernoulli differential equations and their applications
  • Practice integration techniques for rational functions
  • Explore function transformations in differential equations
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Students and educators in mathematics, particularly those focusing on differential equations, as well as anyone looking to enhance their problem-solving skills in this area.

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Homework Statement


I need to find a general function y(x) such that:
\dot y(x) - 2y(x) = y^2(x)-3


Homework Equations





The Attempt at a Solution


I tried dividing the equation by y^2-3 and turn it into a Bernoulli differential equation, but that didn't work. The equation seems relatively simple yet i can't recall any method to solve it. Please help.
 
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It's separable. dy/dx = y2 + 2y - 3 ==> dy/(y2 + 2y - 3) = dx
 
How could i not see that! i solved it, tnx a lot. :)
 

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