Calculating Critical Angle and Single Color Angle in Optical-Quality Glass

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The discussion focuses on calculating the critical angles for red and violet light in optical-quality glass with an index of refraction of 1.520 for red and 1.538 for violet. The critical angles calculated are 41.1 degrees for red and 40.6 degrees for violet, indicating that red light will disappear first due to total internal reflection. The overall critical angle for the glass itself is 41.0 degrees. Therefore, at angles greater than 41.0 degrees, only violet light will be visible. The calculations and conclusions presented are confirmed as correct.
mr.miagi
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Help!Physics II question!

A white light source is below the lower surface of a piece of optical-quality glass. The glass has an index of refraction of 1.520 for red light and 1.538 for violet. If you were able to move your eye at any angle relative to the perpendicular to the glass, calculate A) Which color disappears first due to total internal reflection B) At what angle do you see only a single color, red or violet?
 
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So far I have done the following
critical angle = sin-1(1.00/1.520) =41.1degrees for red
critical angle = sin-1(1.00/1.538) =40.6degrees for violet
The index of refraction for glass is 1.523
critical angle = sin-1(1.00/1.523) = 41.0 degrees
Therefore the red light would disapear first because its critical angle is bigger then that of 41.0 degrees.
part B) the angle would be anything greater then 41.0degrees the only the violet light would be visible.
Is this correct?
 
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