Calculating Tension and Acceleration in a Rotating System

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To calculate the tension and acceleration in a rotating system, apply Newton's second law to both the mass and the wheel. The equation mg - T = ma represents the forces acting on the mass, while the torque on the wheel can be expressed as Torque = Iα. By relating linear acceleration (a) to angular acceleration (α) through the equation a = Rα, the tension can be derived. The final expressions for acceleration and tension are a = mgr/(I + mR^2) and T = mR^2g/(I + mR^2), respectively. This method effectively combines linear and rotational dynamics to solve the problem.
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An object of mass m is tied to a light string wound around a wheel that has a moment of inertia I and radius R. The wheel bearing is frictionless and the string does not slip. find the tension and the acceleration of the object.

I think mg-T=ma


and that I=MR^2

thats all i know can someone help me please

thank you
 
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You need to apply Newton's 2nd law to each body: the mass and the wheel.
Originally posted by bard
I think mg-T=ma
Right. That's Newton's 2nd law applied to the mass.

Now apply it to the wheel, using the rotational form: Torque = I*α (you tell me the torque).

To relate the two equations, note that a = R*α.
 
Hi Doc Al,

Almost solved it
the a i use here will be angular acceleration

so

net torque=T*R or

Ia=T*R

Ia=(mg-mRa)R

Ia=mgr-mR^2a

Ia+mgR^2a=mgr
a(Ia+mR^2)=mgr

a=mgr/I+mR^2

for acceleration the tension is a=mR^2g/(I+mr^2)
 
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