Help:Projectile Motion - Solve Angle & Hill Height

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SUMMARY

The discussion focuses on solving a projectile motion problem involving a projectile launched from a hill and a boat moving at a constant velocity of 20 ft/s. The initial velocity of the projectile is given as 96.6 ft/s, and the horizontal distance to the boat is 301 ft. To determine the angle of launch and the height of the hill, the user needs to calculate the horizontal and vertical components of the initial velocity and analyze the parabolic trajectory to find the intersection point with the boat's path after 5 seconds.

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**help:projectile Motion***

im giving a problem where i have to find the angle a projectile situated at the top of a will hit an boat wit constant velocity 20 ft/s 5 sec after starting at Vo = 96.6 ft/s and also how high the hill is above the water. The distance from the base of the hill to the boat is given to be 301 ft. Do i need to find the (Vo)x and (Vo)y with tan (-1) in order to get the angle and can i just assume the triangle to be a 3-4-5 triangle?
 
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This is a homework problem and should be posted in the Homework section - Introductory Physics - would be appropriate.

One basically has to find the parabolic trajectory of the projectile and where it intersects the boat after the projectile and the boat both travel some distance during 5 seconds.

The distance from the base of the hill to the boat is given to be 301 ft.
It would appear that the boat starts 301 feet from the point even with the projectile. The horizontal velocity of the projectile must be such that it travels the initial distance from the boat + boat distance traveled by boat in 5 seconds.

:cool:
 

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