Help proving complex inequality

  • #1
58
0
This may seem trivial, but for some reason I am having trouble with it. For a and b in the complex plane, I am trying to prove the following:

|a|^2+|b|^2 >= |(a+b)/2|^2

I need this for part of a larger proof.
 

Answers and Replies

  • #2
Since no one has answered yet, I'll give it a go.

Starting from the triangle inequality, we get

|a+b| <= |a| + |b|

=>

|a+b|^2 <= (|a| + |b|)^2 = |a|^2 + |b|^2 + 2|a||b|

=>

|(a+b)/2|^2 <= |a|^2 / 4 + |b|^2 / 4 + |a||b| / 2


If we can prove that |a|^2 + |b|^2 >= |a|^2 / 4 + |b|^2 / 4 + |a||b| / 2, then we're done!

Can you go from here?
 

Suggested for: Help proving complex inequality

Replies
13
Views
430
Replies
13
Views
306
Replies
2
Views
554
Replies
10
Views
657
Replies
2
Views
119
Replies
4
Views
633
Replies
0
Views
469
Replies
7
Views
384
Replies
3
Views
726
Replies
7
Views
703
Back
Top