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Help simple c program with loop, not running through each integer.

  1. Aug 15, 2012 #1
    1. The problem statement, all variables and given/known data

    I want to create a program that prints the sum of integers k for k(1-20)


    k sum
    1 1
    2 3
    3 6
    4 10
    5 .
    6 .
    20 .

    in that format

    2. Relevant equations

    3. The attempt at a solution

    #include <stdio.h>

    int main(int argc,char * argv[]){
    int i=0, sum=0, n=20;
    for (i=0;i<n;++i);{


    printf("%d = %4d\n",i, sum);

    return 0;

    I don't want the user to enter an input (hence no scanf) I just want the program to run through integers 1-20 and print there sum.

    when I run this it just prints 20 = 20??

    help please!!

  2. jcsd
  3. Aug 15, 2012 #2


    Staff: Mentor

    you put a semicolon in a bad spot

    for ( ... ) ;{ ...code block... }

    just runs the for loop but not the code block

    try this:

    for ( ...) { ...code block... }

    this is a famous gotcha that many programmers do at one time or another
  4. Aug 15, 2012 #3
    Ohh wow that worked... I was stuck on that for a while... no pun intended:)
  5. Aug 15, 2012 #4
    and now try without a loop
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