Help Solve Impulse Problem w/ Pendulum Bob

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SUMMARY

The discussion centers on calculating the impulse delivered to a pendulum bob by a bullet. The bullet, with mass m and initial speed v, passes through the bob of mass M and exits with speed v/2. The impulse is calculated using the formula for momentum change: impulse = P_f - P_i, where P_f is the final momentum and P_i is the initial momentum. The user attempts to derive the impulse but expresses uncertainty about the final answer, indicating a need for further clarification on the velocity of the bob after the bullet passes through.

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HELP!Impulse problem

Homework Statement


A bullet of mass m and speed v passes through a pendulum bob of large mass M and emerges with speed v/2. the bob is at the end of a sting of length l.What impulse is delivered to the bob by the bullet in this case.

The Attempt at a Solution


impulse=momentum change=P_f-P_i
therefore,
impulse=(m(v/2)+Mv')-mv

However, I don't think it is the final answer for this question, but I don't really know how to continue... can anyone help me with this question? thank you very much.
 
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I see nothing is wrong. The bullet comes in with v while the bob has v=0 then the bullet exits with v/2 and then the bob has a velocity of v' (or some velocity v)
 


djeitnstine said:
I see nothing is wrong. The bullet comes in with v while the bob has v=0 then the bullet exits with v/2 and then the bob has a velocity of v' (or some velocity v)

thank you very much. I am just making sure.
 

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