Max Impulse on a pendulum

  • #1
PakBosMuda
1
0
TL;DR Summary: An impulse is given to the pendulum so that it moves in 3 dimensions. What equations apply throughout its motion?

A particle of mass ##m## is suspended from a string of length ##\ell##. The string is then deflected at an angle ## \theta ##, where the particle and string are in the XY-plane.
Capture.PNG


What is the maximum impulse in the Z-axis direction so that the particle does not hit the roof?
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What I already know (CMIIW):

1. Throughout its motion, the energy of the particle is conserved:
$$E_{i} = E_{r}$$
$$PE_{i} + KE_{i} = PE_{r} + KE_{r}$$
$$-m.g. \ell . \cos \theta + \frac{1}{2} . m . v_{i}^2 = 0 + \frac{1}{2} . m . v_{r}^2$$
$$v_{i}^2 = 2g. \ell . \cos \theta + v_{r}^2$$

2. The condition for a particle not to hit the roof is that its final velocity vector (when on the roof) is in the XZ-plane ##\rightarrow \left( v_r \right) _y = 0##
1.jpg


3. Angular momentum is NOT CONSERVED, because the weight creates torque (as well as linear momentum).

There are 2 unknown variables : ##v_i## and ##v_r##, while the only equation I have is energy conservation. What am I missing?
 
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  • #2
This is nothing but a spherical pendulum. Angular momentum in what you have lanelef the y-direction is conserved due to rotational symmetry about the y-axis.

Also, please do not use periods as multiplication in ##\LaTeX##. Leaving the multiplication operator is fine.
 

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