Help Solve PH Homework: NaOH + H20 at 25degrees

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Discussion Overview

The discussion revolves around a homework problem involving the dissolution of sodium hydroxide (NaOH) in water and the calculation of hydronium ion concentration ([H3O+]) at 25 degrees Celsius. Participants explore the chemical equations involved and the relationships between pH, pOH, and ion concentrations.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • One participant presents a homework statement involving the addition of NaOH to water and seeks help with the calculation of [H3O+].
  • Another participant suggests calculating [OH-] first and then using the relationship pH + pOH = 14 to find [H3O+].
  • A participant mentions the water ion product, possibly indicating its relevance to the calculations.
  • There is a request for assistance in balancing the chemical equation for the dissociation of NaOH.
  • Participants discuss the correct representation of the dissociation of NaOH, with one suggesting NaOH > Na+ + OH-.
  • Another participant emphasizes the importance of considering charges in the ionic equation.

Areas of Agreement / Disagreement

Participants generally agree on the need to calculate [OH-] and the dissociation of NaOH, but there is no consensus on the specific steps or equations to use, indicating multiple competing views on how to approach the problem.

Contextual Notes

Some participants express uncertainty about balancing the chemical equation and the correct representation of the dissociation process. There are also unresolved aspects regarding the calculation of [H3O+].

Who May Find This Useful

Students working on acid-base chemistry, particularly those dealing with calculations involving strong bases and their dissociation in water.

geffman1
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Homework Statement


We add 0.535 g of NaOH to 100.0 mL of water at 25degrees. What is [H3O+] in this solution at 25degrees?

hey guys, I've practiced these types of questions a lot, but I've never came across one like this before. i tried writing equations and i got this 2NaOH+2H20>>2Na+2H30, but I am stuck at the next step. anyhelp would be good. thanks

ANSWER=7.48 x 10-14 M

(p.s) if anyone could sit down with me on msn or something for 20minutes I've got about 15 basic question i need help with (ive got the answers). thanks
 
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If that NaOH concentration is not too excessive for the model, you can try finding expected [OH-] and then use pH + pOH = 14
 
ta, could you help me write the equation then because i can't get it to balance good? tnaks
 
Your equation won't have H+ in it.

Check the page I have lined to. To start you have to calculate [OH-].
 
can i just write it like this..NaOH>Na+OH
 
Don't ignore charges, these are ions. But otherwise you are on the right track, this is just a simple dissociation.
 

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