Help Solving a Distance-Time Graph Problem

  • Thread starter Thread starter HelloMotto
  • Start date Start date
  • Tags Tags
    Graph
Click For Summary

Homework Help Overview

The discussion revolves around a distance-time graph problem, where the original poster is attempting to determine the distance traveled after a specified time using a plotted graph and a best-fit line.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants explore the interpretation of the question regarding distance traveled after 5 minutes, with some questioning the understanding of derivatives and integrals. Others clarify the concept of distance as a change in position based on the graph.

Discussion Status

The discussion has progressed with some participants providing clarifications and guidance on interpreting the question. The original poster has acknowledged a misunderstanding of the question and seems to be moving towards a resolution.

Contextual Notes

The original poster mentions being in a grade 10 science class, indicating a potential limitation in their familiarity with certain mathematical concepts like derivatives.

HelloMotto
Messages
73
Reaction score
0
hi.

ok so my question is related to distance-time graphs
A chart was given, i plotted it on to graph and drew a bes-fit straight line.

One of the question asks "using your graph, find the distance traveled after 5.0 min."

ok i found the slope of the line between 5min and the last point, which is 12 min.

The problem is i forget what to do next lol. :blushing: Could anyone help me please?
 
Physics news on Phys.org
are you working with derivatives or integrals?
 
jcsolis said:
are you working with derivatives or integrals?

oh umm. i don't know what derivatives mean lol. i checked my textbook and i can't find those terms.
its a grade 10 science by the way.
 
First, I think when they say find the distance traveled after 5 minutes, I think they mean to find the distance traveled after five minutes has passed, not the distance traveled from the 5 minute mark to the end of the graph.

OK, so you have position graphed on the y axis, correct? If this is the case, can you tell me the position at 0 minutes, and the position at 5min? If you can, just remember that distance is a change in position.
 
umm the at 0 mins the car is not moving so 0 distance. and 5 min the car is at 6.3 km.
 
HelloMotto said:
umm the at 0 mins the car is not moving so 0 distance. and 5 min the car is at 6.3 km.

OK...Read what you just posted. Unless, I'm reading the question incorrectly, I think you just answered your own question.:smile:
 
Last edited:
G01 said:
OK...Read what you just posted. Unless, I'm reading the question incorrectly, I think you just answered your own question.:smile:

LOL. thank you. i misunderstood the question. thanks again.:smile:
 
Your welcome!
 

Similar threads

  • · Replies 9 ·
Replies
9
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 13 ·
Replies
13
Views
4K
  • · Replies 2 ·
Replies
2
Views
6K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 19 ·
Replies
19
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
3
Views
2K
  • · Replies 13 ·
Replies
13
Views
3K
Replies
4
Views
3K