I need to prove how Superman would 'be more powerful than a locomotive.'(adsbygoogle = window.adsbygoogle || []).push({});

http://img221.imageshack.us/img221/5408/diagram8gm.th.jpg [Broken]

From my diagram I need to find out how much power Superman has to put out to be able to pull that train up the track. I know he has to pull the train 8.5m on an inclined plane of 15 degrees.

-I know the train has a mass of 395 300kg.

-I also know the train is applying a force in the opposite direction.

-Coefficient of kinetic friction of a steel on steel is 0.57

-And finally I know the train is putting out 2,387,200W (3, 200hp) to make that applied force.

So Superman has to overcome the FApplied(train) + FFriction + Fgx to be able to pull the train.

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-FN = mgcosx = (395300kg)(9.81m/s^2)(cos15) = 3745757N

-uk = FFriction/FN

FFriction = (0.57)(FN) = 2135081N

-Fgx = mgsinx = (395300kg)(9.81m/s^2)(sin15) = 1003673N

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Okay so I found FFriction and Fgx of the train but I still need the FApplied by the train to know how much force superman needs to apply in the opposite direction to move it up the hill.

I know the train is putting out 2,387,200W of power in the opposite direction. But how can I calculate how much force that is? Maybe I misunderstand the difference between force applied and power?

Please help me in anyway possible.

-Jay

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