Help Solving Renormalization Group Equations

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SUMMARY

The discussion focuses on solving the renormalization group equations presented by Schwartz, specifically the coupled ordinary differential equations (ODEs) for the dimensionless couplings λ₄ and λ₆. The equations are given as Λ(d/dΛ)λ₄ = aλ₄ + bλ₆ and Λ(d/dΛ)λ₆ - 2λ₆ = cλ₄ + (d+2)λ₆. The user seeks clarity on the transition from equation (120) to (121) and from (122) to (123), which involves approximating small constants a, b, c, and d, and understanding the implications of these approximations on the solutions. The user ultimately resolves their confusion regarding these transitions.

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  • Understanding of renormalization group theory
  • Familiarity with ordinary differential equations (ODEs)
  • Knowledge of dimensionless couplings in quantum field theory
  • Ability to interpret mathematical notation and equations
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  • Study the derivation of renormalization group equations in quantum field theory
  • Learn about the diagonalization of matrices in the context of coupled ODEs
  • Explore the significance of relevant and irrelevant operators in renormalization
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The discussion is beneficial for theoretical physicists, graduate students in physics, and researchers focusing on quantum field theory and renormalization group analysis.

Sonny Liston
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This isn't a homework problem, but something from a set of notes that I'd like to better understand. My confusion starts on page 23 here: http://isites.harvard.edu/fs/docs/icb.topic1146665.files/III-9-RenormalizationGroup.pdf. I'm having trouble reproducing his calculation for the marginal/irrelevant couplings from the notes, and would like to solve problem 5 at the end. I'm hoping that understanding what he does in the notes will help my current confusion about that problem, which I think promises a really nice understanding of why relevant operators are problematic.

Homework Statement


Schwartz starts with the general renormalization group equations \Lambda \frac{d}{d\Lambda} \lambda_{4} = a\lambda_{4} +b\lambda_{6} and \Lambda \frac{d}{d\Lambda} \lambda_{6} -2\lambda_{6} = c\lambda_{4} + (d+2)\lambda_{6} where \lambda_{4},\lambda_{6} are dimensionless couplings and a,b,c,d are small constants. At this point, the problem just becomes solving this set of coupled ODEs, which Schwartz does by diagonalizing the matrix \bigl( \begin{smallmatrix} <br /> a &amp; b\\<br /> c &amp; d+2 <br /> \end{smallmatrix} \bigr)

This eventually leads to exact solutions in the basis we began with, which are given by eqns. (118) and (119) in his notes.

Homework Equations


The part of the reasoning that I'm confused about is how he goes from eqn. (120) to eqn. (121), and later from (122) to (123).

Eqn (120) is \lambda_{6}(\Lambda)=\lambda_{4}(\Lambda) \frac{2c[(\Lambda/\Lambda_{H})^{\Delta}-1]}{(2+d−a+\Delta)-(2+d−a-\Delta)(\Lambda/\Lambda_{H})^{\Delta}}

and Schwartz claims that Setting \Lambda=\Lambda_{L}\ll\Lambda_{H} and assuming a, b, c, d\ll 2 so that \Delta\approx 2 we find Eqn(121), which is \lambda_{6}(\Lambda_{L})=\lambda_{4}(\Lambda_{L})[\frac{c}{2}((\Lambda_{L}/\Lambda_{H})^2 -1]

I'll list my confusion for this case below, but similar confusion extends to moving from (122) to (123).


The Attempt at a Solution



I can come up with a justification for getting eqn (121) from eqn (120), but it seems likely wrong: since both d,a are small and \Delta\approx 2 and (\Lambda_{L}/\Lambda_{H})^2 is very small since \Lambda=\Lambda_{L}\ll\Lambda_{H} we can neglect the d-a and (d-a)(\Lambda_{L}/\Lambda_{H}) terms which allow us to approximate the denominator in (121) by 4. This then gives us eqn (121).

I mentioned I'm suspicious of this reasoning, but does this seem sound? It also seems justify the move from (122) to (123). And if so, does anyone have guidance on how to tackle problem 5 in those notes?
 
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Nevermind -- got it sorted.
 

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