Help w/ projecetile motion w/ angled launch problem

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Homework Help Overview

The problem involves a bowling ball rolling off an angled roof, which is sloped at 18.4 degrees and 12 meters above the ground. The main question is to determine how long it takes for the ball to hit the ground after leaving the roof.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the use of kinematic equations and the challenges in isolating time (t). There are attempts to apply the quadratic formula, with one participant suggesting a calculated time of 1.56 seconds but expressing uncertainty about its correctness. Questions arise regarding the speed of the ball as it leaves the roof and the interpretation of the time being sought.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem and questioning the sufficiency of the provided information. Some participants suggest that the problem may be incalculable due to missing details, while others seek clarification on the exact wording of the question.

Contextual Notes

There is uncertainty regarding whether the time requested is for the ball's fall after leaving the roof or includes the time taken while rolling down the roof. The angle of the roof is noted as potentially significant, but its role in the calculations is not fully explored.

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Homework Statement


A bowling ball rolls off an angled roof. The roof is sloped downward at 18.4 degrees and it is 12m above the ground. The question is how long does it take the ball to hit the ground?

Homework Equations


Δx=viΔt+1/2a(Δt)^2
I know this is the equation I have to use but I'm having trouble isolating t.

The Attempt at a Solution


I used quad formula and ended up getting Δt=1.56s but I don't think that's right. The working equation I got was Δt=(-2ghi)^(1/2)/g .I assumed Vi was 0. I don't know how to do this, help please!
 
Last edited:
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physicsgeek54 said:

Homework Statement


A bowling ball rolls off an angled roof. The roof is sloped downward at 18.4 degrees and it is 12m above the ground. The question is how long does it take the ball to hit the ground?

Homework Equations


Δx=viΔt+1/2a(Δt)^2
I know this is the equation I have to use but I'm having trouble isolating t.

The Attempt at a Solution


I used quad formula and ended up getting Δt=1.56s but I don't think that's right. The working equation I got was Δt=(-2ghi)^(1/2)/g .I assumed Vi was. I don't know how to do this, help please!

How far down the roof did the ball roll before launching of the edge? In other words; at what speed did the ball leave the roof?

EDIT: and is the time you are after, the time taken after it leaves the roof, or the time taken after it was released at the ridge of the roof and began rolling?
 
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I think it might be missing some information.

the angle is there for some reason.
 
That's all the info to this problem and I would assume it's asking for how the ball takes to hit the ground after it's left the roof.
 
physicsgeek54 said:
That's all the info to this problem and I would assume it's asking for how the ball takes to hit the ground after it's left the roof.


If that is all the information that is provided then the answer is: "this problem is incalculable due to insufficient information"

Have you entered the question in the exact words in which the original question was stated?

It looks more like your interpretation of the question.
 
Well, here's the exact question. A bowling ball rolls off an angled roof. The roof is sloped downward at 18.4°, and the eaves are 12.0 meters above the ground. a.)How long does it take the ball it hit the ground?
 
physicsgeek54 said:
Well, here's the exact question. A bowling ball rolls off an angled roof. The roof is sloped downward at 18.4°, and the eaves are 12.0 meters above the ground. a.)How long does it take the ball it hit the ground?

What is part b, c, etc
 

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