Solving for Time and Velocity of a Ball Rolling Off a Table – Motion Question

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Homework Help Overview

The problem involves a ball rolling horizontally off a table that is 1.00 m high, striking the floor 1.64 m away from the table edge. Participants are tasked with determining the time the ball was in the air and its initial speed upon leaving the table, while neglecting air resistance.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the use of kinematic equations to relate horizontal and vertical motion. Questions arise regarding the initial vertical velocity (V0y) and the acceleration in the horizontal direction.

Discussion Status

Some participants have confirmed the correctness of the equations used, while others express uncertainty about finding the initial vertical velocity. There is a focus on clarifying the implications of the ball rolling off horizontally.

Contextual Notes

Participants note the challenge of working with limited information and the need to clarify assumptions about initial velocities in different directions.

kevinf
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Homework Statement


A ball rolls horizontally off the edge of a tabletop that is 1.00 m high. It strikes the floor at a point 1.64 m horizontally away from the table edge. (Neglect air resistance.). How long was the ball in the air and what speed was it at the instant it left the table.


Homework Equations


x-x0 = V0xT + .5(a)t^2

y-y0 = V0yT - .5(g)t^2

The Attempt at a Solution


i am having trouble figuring out anything with this little information. i have tried to use the equations that i provided but it was missing velocity. any other way that i can do that i may have missed?
 
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kevinf said:

Homework Statement


A ball rolls horizontally off the edge of a tabletop that is 1.00 m high. It strikes the floor at a point 1.64 m horizontally away from the table edge. (Neglect air resistance.). How long was the ball in the air and what speed was it at the instant it left the table.


Homework Equations


x-x0 = V0xT + .5(a)t^2

y-y0 = V0yT - .5(g)t^2

The Attempt at a Solution


i am having trouble figuring out anything with this little information. i have tried to use the equations that i provided but it was missing velocity. any other way that i can do that i may have missed?
Your equations are correct. What is the value of V0y? What is the value of 'a' in the x direction?
 
yeah but i don't know how to find V0y with that information
 
kevinf said:
yeah but i don't know how to find V0y with that information
it's given that the ball rolls off the table horizontally. So what is its initial speed in the y direction if it initially is moving horizontally in the x direction only?
 
thanks i got the answer.
 

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