Help What is wrong with this proof?

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The discussion revolves around a proposed proof of the Goldbach Conjecture, asserting that every even integer greater than 4 can be expressed as the sum of two prime integers. Key points include the distinction between sums of odd integers and prime integers, where participants argue about the validity of equating these sums. The proof attempts to establish that any even integer can be represented as both a sum of two odd integers and a sum of primes, but faces criticism for not adequately demonstrating that every even integer has a corresponding pair of prime addends. Participants emphasize the necessity of proving that for each even number, there exists a set of two odd primes that sum to it, which remains unaddressed. The conversation highlights the complexities and challenges inherent in proving the Goldbach Conjecture.
  • #31
mathew3 said:
It must be the latter ;
14532=5+14527
Note however that just stating this alone is not sufficient. To do so declares the summation of pairs of primes by fiat. It must also be linked to the sum of a pair of odd integers.

The former is excluded from consideration because it utilizes more than two odd addends.

14527 is not prime...

OK, please indicate exactly how you would find the decomposition of 14532??
 
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  • #32
micromass said:
14527 is not prime...

I stand corrected. I was lazy and assumed you had included two primes since that is the point of the conjecture.
micromass said:
OK, please indicate exactly how you would find the decomposition of 14532??

Why? As you have indicated it has nothing to do with the problem at hand. And as you well know I could decompose a thousand such numbers\examples and it wouldn't get us one iota closer to proving or disproving the conjecture.
 
  • #33
mathew3 said:
I stand corrected. I was lazy and assumed you had included two primes since that is the point of the conjecture.


Why? As you have indicated it has nothing to do with the problem at hand. And as you well know I could decompose a thousand such numbers\examples and it wouldn't get us one iota closer to proving or disproving the conjecture.

You want to know what is wrong with the proof, right? So I present you with a method how you can get to know that something is wrong: a concrete example.

I want you to apply your method on 14532 to show you that your method does not work. So please, explain how you would apply your method to 14532.
 
  • #34
micromass said:
You want to know what is wrong with the proof, right? So I present you with a method how you can get to know that something is wrong: a concrete example.

I want you to apply your method on 14532 to show you that your method does not work. So please, explain how you would apply your method to 14532.

I thought you were aware of this but apparently not. Even if I supply the two primes it means nothing! I does not and cannot prove the conjecture. All it does is encourage you to keep asking me to solve yet another example.
 
  • #35
mathew3 said:
the two odds can be expressed as 2 primes. There is nothing mathematically that prohibits this.
Yes, but a rigid proof is alleged here and to make a proof you must logically show how your steps lead to the one and only conclusion that for each even number greater than 4, that there necessarily exists at least one pair of primes that sum to each such even number. Myself,
pwsnafu, and Micromass have shown that your proof is lacking in this regard. That is exactly what is wrong with your proof.
 
  • #36
ramsey2879 said:
Yes, but a rigid proof is alleged here and to make a proof you must logically show how your steps lead to the one and only conclusion that for each even number greater than 4, that there necessarily exists at least one pair of primes that sum to each such even number.

I've yet to see how I haven't shown this however I realize this may be tendentious on my part. Again that's why I presented it here on the forum for criticism. I will certainly take your criticisms into consideration and I appreciate your input. Thanks.
 
  • #37
mathew3 said:
I thought you were aware of this but apparently not. Even if I supply the two primes it means nothing! I does not and cannot prove the conjecture. All it does is encourage you to keep asking me to solve yet another example.

Just solve the example with your method... It will tell you why your method is bunk.
 
  • #38
micromass said:
Just solve the example with your method... It will tell you why your method is bunk.
Really, Isn't it possible to establish the numericaL existence of something without actually being able to determine its value? For instance there are tests that show a number to be composite that do not provide any factor of the number.
 
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  • #39
micromass said:
just solve the example with your method... It will tell you why your method is bunk.

14519 +13=14532=14529 +3
 
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  • #40
ramsey2879 said:
Really, Isn't it possible to establish the numericaL existence of something without actually being able to determine its value? For instance there are tests thast show a number to be composite that do not provide any factor of the number.

Indeed, this is possible. But the method of the OP seems to be constructive. Or at least he claims that.

mathew3 said:
I normally resist these juvenile challenges however you need to be taught a lesson...

14519 +13=14532=14529 +3

How did you arrive to this solution?? How did your method help you in getting the solution?? THAT's what I want to know.

Of course, you can find the decomposition easily. I found it very easily using a computer program. But I want you to solve it with your method. You can't because the method is bunk.

Please give me ALL the steps you did in solving this problem. If you can do this, then I'll agree that your method works. You can't however.

(oh, yes, 14529 isn't a prime)
 
  • #41
ramsey2879 said:
Really, Isn't it possible to establish the numericaL existence of something without actually being able to determine its value?

Yup. But that still requires a proof. And it's very hard to do this using only elementary techniques, which is what OP asserts.

OP's argument is basically:
  1. For all even numbers greater than 4, there exists a finite set of primes which sum to it. But not necessarily two primes.
  2. For all even numbers greater than 4, there exist two odd positive integers which sum to it. But not necessarily primes.
  3. The two sums are equal to each other numerically, i.e. the "equal sign" is from PA.
  4. Therefore, for all even numbers greater than 4, there exists two odd primes which sum to it.

It's simply a case of not understanding the "there exists" quantifier properly. His coin analogy is evidence for this.
 
  • #42
pwsnafu said:
Yup. But that still requires a proof. And it's very hard to do this using only elementary techniques, which is what OP asserts.

OP's argument is basically:
  1. For all even numbers greater than 4, there exists a finite set of primes which sum to it. But not necessarily two primes.
  2. For all even numbers greater than 4, there exist two odd positive integers which sum to it. But not necessarily primes.
  3. The two sums are equal to each other numerically, i.e. the "equal sign" is from PA.
  4. Therefore, for all even numbers greater than 4, there exists two odd primes which sum to it.

It's simply a case of not understanding the "there exists" quantifier properly. His coin analogy is evidence for this.

Close. And if that is the logical progression I have portrayed (which I don't think I have) then I have been remiss. There is a huge gaping chasm logically between your 3 and 4. Let's try this :
Your 1,2, and 3
3a. We consider the case where E can only be composed of two and only two odd integers
3b. To this case we then apply your 1.
Therefore your 4.

I'm not familiar with the there exists quantifier and will look it up.
 
  • #43
mathew3 said:
Close. And if that is the logical progression I have portrayed (which I don't think I have) then I have been remiss. There is a huge gaping chasm logically between your 3 and 4. Let's try this :
Your 1,2, and 3
3a. We consider the case where E can only be composed of two and only two odd integers

This case is void. Every nontrivial integer can be decomposed in multiple way as such a sum.

3b. To this case we then apply your 1.

This is false, I'm sorry. You can't apply 1 to anything. I have asked you to write down the method in an example so you could see where it went wrong. You didn't do this.

I'm asking myself this:
- Do you want us to give you a reason why your "proof" is false?
- Do you want to convince us that your "proof" is true?

Your attitude seems to indicate the latter.

If it is the former (which I doubt), then please do as I told. Please write it out in an example. You'll see immediately what goes wrong!
 
  • #44
mathew3 said:
Close. And if that is the logical progression I have portrayed (which I don't think I have) then I have been remiss.

I took your original post, cut all the waffle, and got that.

3a. We consider the case where E can only be composed of two and only two odd integers
3b. To this case we then apply your 1.

More waffle.

3a is meaningless because it says nothing about primality, so its just 2.
3b is meaningless because it is no different to 4.

Note that if you had written
3a. Take 2 and consider the case where E can only be composed of two and only two odd integers
that is a lot worse.

Sorry, everything else you write, whether its analogies, solving examples etc is nothing more than window dressing. You write so much of it to create an illusion of more logic. And you have convinced yourself that there is logic there.
 
  • #45
I think this guy must be a troll...
 

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