Help with Algebra: Circuits & Equations

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SUMMARY

This discussion focuses on algebraic problem-solving related to circuits and equations, specifically addressing the manipulation of equations involving current (I3) and resistance (R). User A137 points out potential errors in the original poster's approach, highlighting issues with multiplying through the common denominator and the accuracy of the denominator itself. The conversation emphasizes the importance of correctly setting up equations and maintaining proper signs throughout the calculations.

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jKotha
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Please look at the attached Microsoft word document because I don't know how to write out everything in this template. I need help with algebra, thanks!
 

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What is the What?

What is the question you are trying to answer?
(The zeroth step in answering a question.)

:cool:

~A137
 
When you were trying to multply through in the common denominator step,
-132E-33I3(330R) - 20I3(200R) -20E = I3
660R
it looks like you are multplying twice? :confused: I don't understand what you are doing there. Also, your denominator isn't correct, what does R*R give you? Be very careful with your signs.

It would help to see the entire problem, especially since I didn't get the same answer as your instructor. Maybe you haven't set up the equation properly?
 
Last edited:

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