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- Homework Statement
- Determine the current flowing through the circuit(attached below) immediately after having closed the switch.

Values of ##V##, ##R_1##, ##R_2## and ##L## are given.

- Relevant Equations
- Ohm's law

Inductance

DISCLAIMER: don't answer in terms of integrals, I haven't covered those yet :)

Hi guys, I'm having a few troubles understanding RRL circuits, and have a few questions for you.

A "normal" RL circuit will have a current growing inversely exponentially, starting from 0 and going to ##V/R## as predicted by Ohm's law.

First question: why, intuitively(not algebraically, I know that in order to demonstrate it we must solve a differential equation), is that true?

Then, coming back to our RRL, should we consider the current flowing through ##R_1##, immediately after closing the circuit, to be ##I=\frac{V}{R_1+R_2}## with regards to the consideration above for an RL circuit, by which we deduce that the current at ##t\approx 0## flowing in the branch with the inductor, is ##I_i\approx 0##?

Hi guys, I'm having a few troubles understanding RRL circuits, and have a few questions for you.

A "normal" RL circuit will have a current growing inversely exponentially, starting from 0 and going to ##V/R## as predicted by Ohm's law.

First question: why, intuitively(not algebraically, I know that in order to demonstrate it we must solve a differential equation), is that true?

Then, coming back to our RRL, should we consider the current flowing through ##R_1##, immediately after closing the circuit, to be ##I=\frac{V}{R_1+R_2}## with regards to the consideration above for an RL circuit, by which we deduce that the current at ##t\approx 0## flowing in the branch with the inductor, is ##I_i\approx 0##?