Help with logistic growth problem

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To solve the logistic growth problem, the differential equation dP/dt = kP(P0 - P) is relevant, where k is the growth rate and P0 is the carrying capacity. The provided data points can be used to estimate the constants k and P0 by analyzing the change in population over time. To predict the population at T=10, one can apply the logistic growth formula using the estimated values of k and P0. It is crucial to ensure that the calculations align with the logistic growth model's characteristics. This approach will guide the prediction of population growth effectively.
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Hi all, I've got this logistic growth problem that I'm unsure of on how to start. I missed a day of class and don't have a chance to go to office hours, so any help would be much appreciated.

I've been given a set of values: time, population, and change in population.

The values are as follows, with each value correlation to each time value of course:
T=0.0, P=2.0, dP/dt=0.11
T=37.71, P=14.0, dP/dt=0.62
T=45.05, P=19.0, dP/dt=0.74
T=57.45, P=29.0, dP/dt=0.84

I've been asked to predict population, P at T=10.

A point in the right direction would be great, thanks.
 
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amazingAZN said:
Hi all, I've got this logistic growth problem that I'm unsure of on how to start. I missed a day of class and don't have a chance to go to office hours, so any help would be much appreciated.

I've been given a set of values: time, population, and change in population.

The values are as follows, with each value correlation to each time value of course:
T=0.0, P=2.0, dP/dt=0.11
T=37.71, P=14.0, dP/dt=0.62
T=45.05, P=19.0, dP/dt=0.74
T=57.45, P=29.0, dP/dt=0.84

I've been asked to predict population, P at T=10.

A point in the right direction would be great, thanks.

The ODE you are trying to solve is
<br /> \frac{dP}{dt} = kP(P_0 - P)<br />
for some constants k and P_0 which you can estimate from the given data for dP/dt and P.
 

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