Help with Mechanics Problem Needed

  • Thread starter cmseybold
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In summary, two horses are pulling a barge at a 30 degree angle with a maximum rate of 2 horsepower each. The tension in the cables can be calculated by multiplying the speed of the horses (1.73 m/s) by their maximum horsepower (1500W). The maximum steady speed of the barge can be calculated by using the horse's power (1500W) and the resistive force of the water (120v) using the formula P = Fv.
  • #1
cmseybold
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Two horses are pulling a barge as shown. Both hourses can each work at a maxiumum rate of 2 horsepower=1500W.

(The picture shows a barge headed in the right direction, with the horses pulling at 30 degrees relative to the displacement. so they are pulling sideways in both directions)

1) When the horses are walking at a steady speed of 1.73 m/s, Calculate the tension in the cables.

2) If the water exerts a resistive force on the barge that varies with the barges speed as 120v (Newtons) where v is the speed of the barge in the water, calculate the maximum steady speed of the barge when each horse is exerting his maximum horsepower.

Any help on this question, especially the second part, would be much appreciated!
 
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  • #2
HINT: P = Fv
 
Last edited:
  • #3
We need the resistance to calculate 1) if I am not mistaken.
 
  • #4
qspeechc said:
We need the resistance to calculate 1) if I am not mistaken.
We don't actually...
 
  • #5
Ok, :)
 

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