Help with PDE: F(t)g(r)+V/R Derivative

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SUMMARY

The discussion focuses on solving the partial differential equation (PDE) given by \(\frac{dx}{dt}=f(t)g(r)+\frac{v}{r}\frac{d (Rx)}{dR}\). The user seeks to understand how the second term modifies the solution derived from the first term alone. The recommended approach is to utilize the Laplace transform method, leading to the general solution expressed as \(x(t,r) = \frac{1}{r}[\int_c^tf(\xi)g(vt-v\xi+r)(vt-v\xi+r)d\xi+F(vt+r)]\), where \(F(z)\) is an arbitrary function and \(c\) is a constant.

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matteo86bo
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I need help with this PDE, it's not an homework, I need to solve it for my thesis and it has physical application...anyway the problem is:
<br /> \frac{dx}{dt}=f(t)g(r)+\frac{v}{r}\frac{d (Rx)}{dR}<br /> <br />

f(t) and g(r) are known.

I can solve the equation with only the first or the second term ...
actually I'm interest in how the second term modify the solution of the equation with the first term only. suggestions?
 
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Your PDE can be solved with help of Laplace transform method. For your purpose it'll be better the following form of general solution ( I assume that in fact R is r)

x(t,r) = \frac{1}{r}[\int_c^tf(\xi)g(vt-v\xi+r)(vt-v\xi+r)d\xi+F(vt+r)],

where F(z) is an arbitrary function, c is an arbitrary constant.
 
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