MHB Help with Pre Calc: Get Answers & Guidance

  • Thread starter Thread starter Samanthalovesmath
  • Start date Start date
Samanthalovesmath
Messages
2
Reaction score
0
8C85DAED-3235-4372-88FB-4B464AD6A4AF_4_5005_c.jpeg
 
Mathematics news on Phys.org
It's easy, let's suppose the quadratic is $ax^2 +bx +c = 0$ From the graph we can say $c= -12$ and if you know that the vertex is given by ( $-b \over 2a$ , $-D \over 4a$ )
Put the values you will get the answer.
 
Seemingly by some mathematical coincidence, a hexagon of sides 2,2,7,7, 11, and 11 can be inscribed in a circle of radius 7. The other day I saw a math problem on line, which they said came from a Polish Olympiad, where you compute the length x of the 3rd side which is the same as the radius, so that the sides of length 2,x, and 11 are inscribed on the arc of a semi-circle. The law of cosines applied twice gives the answer for x of exactly 7, but the arithmetic is so complex that the...
Back
Top