Help with Rotation Freq of 10kg Ball on 5m String

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The discussion centers on calculating the new frequency of a 10kg ball rotating on a massless string when the string's length is reduced from 5m to 3m. Initially, the ball rotates at a frequency of 1 Hz. Using the principles of angular momentum conservation, the new frequency after the string is reeled in is determined to be 5/3 Hz. This conclusion is reached by applying the formula for rotational frequency, which is inversely proportional to the radius of rotation.

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A ball with mass m = 10kg is attached to one end of a massless string of length r = 5m.?
The other end of the string is fixed about a point. The ball rotates about this point at a frequency of 1 Hz/ While the ball is rotating, the string is reeled in until its length r = 3m. If the system is not otherwise disrupted in any way, what is the new frequency of rotation?
25/9 Hz
5/3 Hz
1 Hz
3/5 Hz
9/25 Hz

can you help out this hard and I've tried everything? Please


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