1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Help with simplifying boolean expression

  1. Jan 29, 2015 #1
    < Mentor Note -- thread moved to HH from the technical math forums, so no HH Template is shown >

    (A+B)&(C+D) + (A+B)&(C+D)' + C
    (A+B)&(C+D) + (A+B)&(C'&D') + C by deMorgans
    (A+B)&[(C+D)+(C'&D')] + C by Distributive

    I'm just wondering if I did anything wrong in this simplification or if it can be simplified any further.
    Last edited by a moderator: Jan 29, 2015
  2. jcsd
  3. Jan 29, 2015 #2


    User Avatar
    Science Advisor

    Well, use the distributive law on the first part of first line - (A+B)&(C+D) + (A+B)&(C+D)' = (A+B)&((C+D) + (C+D)') = (A+B) (since P + P' = TRUE).
  4. Jan 29, 2015 #3
    Thanks, I didn't even see that.
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted