- #1

- 51

- 12

Hi,

Hi,

i am quite embarrassed to ask this question, but i am really stuck.

i want to derive length of median of triangle from cosine law and i am getting wrong results. I cannot spot the mistake.

So let's have a triange with sides a,b and c. I would like to find length of a median from vertex A to its opposite side a. Let's call the legth d. So i get two triangles from my original one. One has sides a/2,b,d and the second a/2,c,d. Thus i can write two cosine laws:

$$

a^2/4=b^2+d^2-2*b*d*\cos(\alpha/2)

$$

$$

a^2/4=c^2+d^2-2*c*d*\cos(\alpha/2)

$$

where ##\alpha## is angle in vertex A. When i get rid of cosine and solve for d, i get:

$$

d=\sqrt (b*c+a^2/4)

$$

which is wrong (the answer should look like this https://en.wikipedia.org/wiki/Median_(geometry), or one can just try the formula for equilateral triangle (in this case both equations reduce to the same, but i guess one can take the limit to be able to apply formula even for this case)).

**Can you help me to spot the mistake?**

Thanks:)

Thanks:)