Help with spring rotating around its axis of rotational symm

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Homework Help Overview

The problem involves a rotating garter spring in a space environment, where the astronaut observes the spring rotating at 300 rpm. The spring's circumference is noted to be 1% longer than its rest state, and the task is to calculate the spring constant given specific parameters such as radius and mass.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the relationship between the spring's rotation and its restoring force, considering concepts of rotational kinetic energy and spring potential energy. Questions arise regarding the source of the inward force and the implications of stretching the spring on its rotation.

Discussion Status

Participants are engaging with the physics concepts involved, questioning assumptions about forces and energy. Some guidance has been offered to clarify the relationships between the forces at play and the physical narrative of the spring's behavior as it rotates.

Contextual Notes

There is a mention of a lack of initial state for comparison in the energy approach, and participants are exploring the implications of the spring's stretching on its rotational dynamics. The problem is noted to be from the Canadian Physics Olympiad, which may impose specific constraints on the approach taken.

starlord37
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Homework Statement


An astronaut on a spacewalk loses her grip on a circular garter spring (pictured below). Looking at the spring she notices that it is rotating around its axis of rotational symmetry at a rate of 300 rpm. The circumference of the rotating garter spring is 1% longer than that of the garter spring when at rest. Calculate the spring constant of the spring if the radius of the rotating garter spring is R = 20 cm and its mass is 1 kg. (We are looking for the spring constant of the spring if it were cut open and stretched along a straight line.)

Homework Equations


T= Ia T=dL/dt K=1/2Iw^2 PE=1/2kx^2

The Attempt at a Solution


I tried using energy but then realized I had no initial state to compare it to. Then I tried using forces and torque but got stuck. This problem is problem 2 from the Canadian Physics Olympiad
http://phas-outreach.sites.olt.ubc.ca/files/2015/08/CAP-en-v7.pdf
 
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Welcome to PF.
Did you reason it out? What is the physics at play here?
 
Thanks. Well I figured since it's being stretched, the restoring force of the spring might be why it's rotating. It has some rotational kinetic energy, and we can find that because we're given omega. It also has some spring potential energy. There's a force radially inward with magnitude mv^2/R. And there's a force from the spring in some direction. I think that's all the physics that's going on.
 
OK. You have things a little garbled. Consider:
Where does the radially inwards force (the mv^2/r one) come from?
(Aside: is this the rightbequation? I.e what is m in this equation?)
How does stretching a spring cause it to rotate?

You are looking for a narrative like: as the spring spins faster, it's circumference gets ________ until ... (fill in the blanks.)

Once you understand the physics, you can write it out using maths.
If the unstretched circumference is C, then the stretched circumference is what?
What is the formula relating tension T in the spring to the change in circumference ##\Delta C##
 

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