(adsbygoogle = window.adsbygoogle || []).push({}); Help with Stirlings formula please!!

Show that

4n is equivalent to lambda/n^1/2(16)^n as n-> infinity

2n

Now using

p is eqquivalent to p!/q!(p-q)!

q

and n = (2*pi*n)^1/2(n/e)^n

so 4n = (8*pi*n)^1/2(4n/e)^4n

and 2n = (4*pi*n)^1/2(2n/e)^2n

now try as I might I can't get it to work out - thus being able to find lambda??

perhaps my algebra is not what is used to be!!

Can anyone give me some gentle prods please......

Many thanks

James

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# Help with Stirlings formula please

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