Help with this Ferris wheel rotational physics problem please

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The discussion revolves around solving a physics problem related to a Ferris wheel's rotational dynamics. The user initially sets up equations for forces at the top and bottom of the wheel but arrives at an incorrect mass calculation of 7.9 kg. Feedback indicates a sign error in the user's equations, specifically regarding the direction of gravitational and centripetal forces. By correcting the acceleration equations to reflect downward as positive, the user can resolve the issue. The conversation highlights the importance of correctly identifying force directions in physics problems.
takelight2
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Homework Statement
A woman rides on a Ferris wheel of radius 16m that maintains the same speed throughout its motion. To better understand physics, she takes along a digital bathroom scale (with memory) and sits on it. When she gets off the ride, she uploads the scale readings to a computer and creates a graph of scale reading versus time. (Figure 1) Note that the graph has a minimum value of 510N and a maximum value of 666N. The acceleration due to gravity, g=9.80m/s2.
Relevant Equations
What is the woman's mass?

Express your answer in kilograms.
So this is what I've attempted:

666 = m*a1
510 = m*a2

a1= ac + 9.8
a2= ac-9.8

666 = m(ac+9.8)
510 = m(ac-9.8)

666 = m*ac + m*9.8
510 = m*ac - m*9.8

156 = 2m(9.8)

m = 7.9 kg (which seems very wrong haha)

any ideas?? I thought my reasoning was okay, since I considered that at the top of the wheel (where weight is max), both the centripetal acceleration and the gravitational acceleration point downward, and at the bottom (weight is min) they point in opposite directions so they must subtract.. What am I doing wrong here?
 
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takelight2 said:
What am I doing wrong here?
You are making a sign error. The 510 N and 666 N are in the same direction as g
 
BvU said:
You are making a sign error. The 510 N and 666 N are in the same direction as g

Oh ok. So then i can just change a2= -ac +9.8, making downward positive.

Ok thanks a lot.
 
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