MHB Help with understanding this series

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Can anyone help with this problem. I've tried integral test but seems to be too complicated.View attachment 9622
 

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Linus12351 said:
Can anyone help with this problem. I've tried integral test but seems to be too complicated.
Have you tried looking at [math]\lim_{n \to \infty} \dfrac{a_{n + 1}}{a_n}[/math]?

-Dan
 
Linus12351 said:
Can anyone help with this problem. I've tried integral test but seems to be too complicated.

Easy,

$\displaystyle 0 \leq \sum{\frac{1}{5^{n-1} + 1}} < \sum{\frac{1}{5^{n-1}}} = \sum{ \left( \frac{1}{5} \right) ^{n-1} }$

Since your positive term series is less than a convergent geometric series, your series converges by comparison.
 
For original Zeta function, ζ(s)=1+1/2^s+1/3^s+1/4^s+... =1+e^(-slog2)+e^(-slog3)+e^(-slog4)+... , Re(s)>1 Riemann extended the Zeta function to the region where s≠1 using analytical extension. New Zeta function is in the form of contour integration, which appears simple but is actually more inconvenient to analyze than the original Zeta function. The original Zeta function already contains all the information about the distribution of prime numbers. So we only handle with original Zeta...

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