Help_How to use graph to find focal length?

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Homework Help Overview

The discussion revolves around using a graph to determine the focal length of convex lenses by rearranging the lens equation. The original poster expresses confusion about transforming the lens equation into a linear form suitable for graphing.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to rearrange the lens equation but is uncertain about the correct form to use for graphing. Some participants suggest plotting 1/v against 1/u to create a linear relationship.

Discussion Status

Participants are exploring different ways to graph the lens equation. One participant has successfully entered a function into a graphical analysis tool, indicating some progress in understanding the relationship between the variables.

Contextual Notes

The original poster is grappling with the transformation of the lens equation and the implications for graphing, indicating a need for clarification on the setup and interpretation of the graph.

linda92
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Homework Statement


Rearrange the lens equation to make 1/v the subject of the equation and then write it as a linear equation. This will lead you to a possible graph for data of object distances and image distances from which you will be able to evaluate the focal length f of the convex lenses.

Homework Equations


*lens equation: 1/f=1/u+1/v

The Attempt at a Solution


I don't really understand what I'm supposed to do. I mean, usually we have equations like y=kx and all we do is to find the slope k. But for the equation 1/v=1/f-1/u ? I really don't get this. Should I make it into v=uf/(u-f)? I think that's the right way but I don't know if i can get f using that equation. Please HELP!
 
Last edited:
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Welcome to PF!

Hi linda92! Welcome to PF! :wink:

You want a straight line,

so instead of having v along one axis, you have 1/v instead.

And along the other axis, you have … ? :smile:
 


Hello! Thanks :)

The other side I made it 1/u.
In Graphical Analysis I entered the function "f(x)=1/f-x", with x=1/u, f(x)=1/v..

...And it worked :)
 
linda92 said:
...And it worked :)

:biggrin: Woohoo! :biggrin:
 

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