Heterolytic and Homolytic Cleavage

  • Thread starter Thread starter andyrk
  • Start date Start date
Click For Summary
SUMMARY

Heterolytic cleavage results in the formation of an anion and a cation, which can be prevented from recombining due to the presence of solvent molecules that create a solvent shell around the ions. This process can occur in both aqueous solutions and in isolation, although it is energetically disfavored without sufficient distance between the fragments. Homolytic cleavage generates radicals with unpaired electrons, which are generally unstable and reactive. The cleavage of a bond requires energy input to overcome the bond dissociation energy, which is the energy needed to separate the fragments completely.

PREREQUISITES
  • Understanding of heterolytic and homolytic cleavage mechanisms
  • Familiarity with the octet rule and its implications in chemical bonding
  • Knowledge of bond dissociation energy concepts
  • Basic principles of solvent interactions in chemical reactions
NEXT STEPS
  • Research the role of solvent shells in ionic reactions
  • Study bond dissociation energy calculations and their applications
  • Explore the stability and reactivity of radicals in organic chemistry
  • Investigate the thermodynamics of bond cleavage and formation
USEFUL FOR

Chemistry students, organic chemists, and researchers interested in reaction mechanisms and bond dynamics.

andyrk
Messages
658
Reaction score
5
When heterolytic cleavage occurs, an anion and a cation are formed. Why don't they get attracted towards each other to form an ionic bond? And does this cleavage occur in an aqueous solution or just by itself?

Similarly, when homolytic cleavage occurs, none of the atoms produced have a complete octet as before. So why did the cleavage occur?
 
Chemistry news on Phys.org
andyrk said:
When heterolytic cleavage occurs, an anion and a cation are formed. Why don't they get attracted towards each other to form an ionic bond? And does this cleavage occur in an aqueous solution or just by itself?
They do attract. Generally, though, something keeps them from recombining. In solution, solvent molecules can form a complex around the newly formed ions called a solvent shell. Even without solution, heterolytic cleavage can still happen, but it's often disfavored energetically because, as you have pointed out, you have to get the fragments far enough away from each other that they don't react immediately.
andyrk said:
Similarly, when homolytic cleavage occurs, none of the atoms produced have a complete octet as before.
Homolytic cleavage of a bond in a closed-shell species (a "normal" chemical compound that obeys the octet rule or otherwise has a complete valence shell without unpaired electrons) generates radicals, which are species with unpaired electrons, or (sticking with the octet rule) unfilled octets. Just because a compound no longer obeys the octet rule doesn't mean it doesn't exist. But the octet rule does allow you to predict that radicals are generally unstable and reactive--although there are exceptions here as well.
andyrk said:
So why did the cleavage occur?
A bond doesn't usually cleave spontaneously. A chemical bond in equilibrium represents a minimum in potential energy, so that to break the bond requires adding energy to the system. So to break a bond, you pump energy into it to push the two fragments apart. For each extra unit of length you stretch the bond, the amount of extra energy required gets a little less until you asymptotically approach what's known as the bond dissociation energy. This is the amount of energy required to separate the fragments by an infinite distance (which is a pretty good definition for a broken bond).
 

Similar threads

Replies
2
Views
2K
  • · Replies 7 ·
Replies
7
Views
5K
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
4
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 7 ·
Replies
7
Views
10K
  • · Replies 5 ·
Replies
5
Views
5K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K