Heuristic explanation of why quantum mechanics plus SR imply antiparticles

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SUMMARY

The discussion provides a heuristic explanation of how quantum mechanics combined with special relativity necessitates the existence of antiparticles. The modification of the Schrödinger equation to accommodate the energy-momentum relation leads to the Klein-Gordon equation, which introduces negative-energy states. This instability is resolved by quantizing a continuous field, where complex-valued fields yield both particle and antiparticle solutions. The conversation also touches on the implications of locality and non-local correlations in quantum theories.

PREREQUISITES
  • Understanding of quantum mechanics and special relativity
  • Familiarity with the Schrödinger equation and its modifications
  • Knowledge of the Klein-Gordon equation and its implications
  • Concepts of local and non-local theories in quantum physics
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  • Study the derivation and implications of the Klein-Gordon equation
  • Explore the concept of quantizing fields in quantum field theory
  • Research the relationship between energy, momentum, and mass in special relativity
  • Investigate the nature of entanglement and its correlation with locality
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Physicists, students of quantum mechanics, and anyone interested in the foundational aspects of quantum field theory and the nature of antiparticles.

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heuristic explanation of why quantum field theory imply antiparticles

I'm looking for a heuristic explanation of why quantum mechanics plus special relativity requires antiparticles, Does anybody want to take a crack at it? Or am I asking for the impossible?
 
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Quantum mechanics plus special relativity does not necessarily require antiparticles: although it naturally accommodates them.

----The straightforward generalization of quantum mechanics to include special relativity requires a modification of the Schrödinger equation. Modifying the Hamiltonian to reflect the energy-momentum relation, E=\sqrt{m^2c^4+p^2c^2}, for relativistic particles,

\hat{H}=\sqrt{-\hbar^2c^2\nabla^2+m^2c^4}\,,​

leads to a non-local theory due to the differential under the square-root.

----Modifying the entire time-dependent Schrödinger equation to reflect the squared energy-momentum relation E^2=m^2c^4+p^2c^2 gives

-\hbar^2\frac{\partial^2}{\partial t^2}\psi(\mathbf{x},t)=-\hbar^2c^2\nabla^2+m^2c^4\psi(\mathbf{x},t)\,,​

the Klein-Gordon equation. While this gives a local theory, it contains negative-energy states in its spectrum. This is a problem since perturbations can cause transitions indefinitely into lower states (hence, this theory is unstable).

----The modern view is to abandon any attempt to directly modify the Schrödinger equation, and instead, to quantize a continuous field, \phi(\mathbf{x},t), using ordinary quantum mechanics. The fields that are quantized, however, have dispersion relations of the same form as the squared energy-momentum relation E^2=m^2c^4+p^2c^2, with the energy, E, identified as the frequency, \omega_p, of propagating plane waves. The resulting Schrödinger equation, has no negative energy solutions, and is local. There are, however, negative frequency solutions associated with the field's dispersion relations.

In the case that a real-valued field is quantized, negative and positive frequency solutions are identified, and there are no antiparticles. In the case that a complex-valued field is quantized, negative and positive frequency solutions are the particle and anti-particle solutions, respectively.
 
TriTertButoxy said:
The resulting Schrödinger equation, has no negative energy solutions, and is local. There are, however, negative frequency solutions associated with the field's dispersion relations.

"Local" in which sense? For example, no non-local communication, or even no non-local correlation in entanglement? (If I may ask at the risk of going off-topic).

My understanding from articles and discussions of about a year ago is that (at least most) local theories require hidden variables, and that a large class of hidden-variable theories has meanwhile been disproven, that entanglement correlations are considered to demonstrate non-local correlations, even though this question is still somewhat open. "Non-local correlations" means that the effects are symmetric from each particles point of view, and therefore not usable for communication, which would require an asymmetric effect.
 
I'm sorry about the confusion:
By local I meant microcausal. That is, the commutators of observables (built out of field operators) with a space-like separation vanish. This ensures that two measurements with a space-like separation do not interfere with each other (no information propagates faster than the speed of light). However, observables with space-like separations may still be correlated giving rise to entanglement.
 
I think it depends on what you mean by "heuristic" - if it means "I want to understand the theory without understanding the mathematics behind it", the answer is no. If you're willing to live with an idea that's not too wrong, it's because the relationship between energy, momentum and mass in SR is quadratic, and just as you get two solutions to the quadratic equation, you get two particles of identical mass.
 

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