Hi,I have:AX + X = B, all of them being matrices. I have the

[Peter G.]

Hi,

I have:

AX + X = B, all of them being matrices. I have the numbers in the A and B matrices and I have to find the exact values of a,b,c,d (numbers in the X matrix)

I wanted to check if my method is correct:

I multiplied both sides by A^-1.

2X = A^-1B

So my values for abcd would be half of the matrix I get when I multiply A^-1 by B:

Thanks,
Peter G.

 

[stringy]

That's not quite right. We'd have

$$AX +X = (A+I)X =B,$$

so if A+I were invertible then $X = (A+I)^{-1}B$.

 

[Mark44]

AX + X = B, all of them being matrices. I have the numbers in the A and B matrices and I have to find the exact values of a,b,c,d (numbers in the X matrix)

I wanted to check if my method is correct:

I multiplied both sides by A^-1.

2X = A^-1B

To elaborate on what stringy said, here is apparently what you did:
AX + X = B
A^-1AX + X = A^-1B
X + X = A^-1B
2X = A^-1B

Step 2 above is incorrect - you didn't multiply the entire left side of the equation by A^-1.

 

[Peter G.]

Hey guys,

Thanks a lot for the help. Impressive how the "Matrix World" can make me commit mistakes I probably wouldn't in the "Real Number World"

Thanks,
Peter