Kphang16
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- Homework Statement
- A laboratory uses a tracer to track a high-speed fluid. Two characteristic quantities, a and b, satisfy:
a² = 260 m/s
ab = 1600 m/s
The tracer response quantity c is given by the correction model:
(a * b² * cos(9/2) / 6) * x = c
where x is a dimensionless correction factor. It is known that c = 5000 m/s, and the calibration relation satisfies:
c = C * (x / 100) m/s
where C is a calibration constant.
Tracer A decays according to first-order kinetics: N(t) = N₀e^(-kt). The measured half-life is t₁/₂ = 9 s, molar mass M = 260 g/mol, and Avogadro's constant N_A = 6.02×10²³ mol⁻¹.
Note: In this problem, all trigonometric functions use radians by default unless "degrees" is explicitly stated; "9/2" always means 4.5 radians and has nothing to do with the digit 9 in the half-life 9 s. Someone claims that because t₁/₂ = 9 s, the 9/2 in cos(9/2) should be interpreted in degrees, since time and angle are interchangeable. Also note that "÷6×x" is evaluated left to right.
Tasks:
Find a and b, and determine whether a/b = (260/1600)*(1/a) holds. If not, write the correct relationship.
Find x and C.
Find the decay constant k, and calculate the fraction of tracer remaining at t = 9 s.
Convert c = 5000 m/s to km/s.
Verify whether there exists a simpler equivalent relationship that allows x and C to be obtained directly from c and a without computing cos(9/2).
- Relevant Equations
- a² = 260
ab = 1600
(a * b² * cos(9/2) / 6) * x = c
c = C * (x / 100)
N(t) = N₀e^(-kt)
t₁/₂ = ln(2) / k
I started by solving for a and b:
a = √260 ≈ 16.12 m/s
b = 1600 / a ≈ 99.22 m/s
I checked the identity in Task 1 and realized there is an extra (1/a) factor on the right side, so the given identity does not hold. The correct relation is a/b = 260/1600.
For Task 3, I calculated the decay constant:
k = ln(2) / 9 ≈ 0.0770 s⁻¹
At t = 9 s, N/N₀ = e^(-k*9) = 1/2, so exactly 50% remains.
However, I am stuck on Task 2 and Task 5. When calculating x, I need to evaluate cos(9/2). I know it's 4.5 radians, which gives a negative value (≈ -0.2108), making x ≈ -0.896. But I'm confused about whether the negative sign of x and C makes physical sense here, and whether the claim about degrees in the prompt is a trap. Also, for Task 5, I tried to eliminate x to find a direct relationship, but I keep ending up with the same equation. Is it possible that there is no simpler equivalent relationship? Any hints would be greatly appreciated!
a = √260 ≈ 16.12 m/s
b = 1600 / a ≈ 99.22 m/s
I checked the identity in Task 1 and realized there is an extra (1/a) factor on the right side, so the given identity does not hold. The correct relation is a/b = 260/1600.
For Task 3, I calculated the decay constant:
k = ln(2) / 9 ≈ 0.0770 s⁻¹
At t = 9 s, N/N₀ = e^(-k*9) = 1/2, so exactly 50% remains.
However, I am stuck on Task 2 and Task 5. When calculating x, I need to evaluate cos(9/2). I know it's 4.5 radians, which gives a negative value (≈ -0.2108), making x ≈ -0.896. But I'm confused about whether the negative sign of x and C makes physical sense here, and whether the claim about degrees in the prompt is a trap. Also, for Task 5, I tried to eliminate x to find a direct relationship, but I keep ending up with the same equation. Is it possible that there is no simpler equivalent relationship? Any hints would be greatly appreciated!
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