Hiking Adventure: 25km SE and 40km N of East!

[r-soy]

A hiker begins a trip by first walking 25.0 km southeast from camp. On the second day she walks 40.0 km in a direction 60.0 north of east, at which point she discovers a forest ranger's tower.

my answer is :

Ax = A cos (60 )

R= A+B = 25 + 40 = 65

thanks

 

[Mark44]

A hiker begins a trip by first walking 25.0 km southeast from camp. On the second day she walks 40.0 km in a direction 60.0 north of east, at which point she discovers a forest ranger's tower.

my answer is :

Ax = A cos (60 )

R= A+B = 25 + 40 = 65

thanks

What is the question?

 

[eumyang]

Usually questions like these ask the distance from the beginning point to the ending point, and the bearing. Though the work the OP given doesn't make sense. Let the camp be point C, let the spot where the hiker rested after the 1st day be point R, and let the tower be point T.

You have a triangle. Sides CR and RT are known, plus angle R (you need to figure the angle out based on the information given). Use the Law of Cosines to find side CT (the distance from the camp to the tower). Use either the Law of Cosines or the Law of Sines to find angle C.

Now, angle C is NOT the bearing. You'll need to look at a diagram and figure out how to get the bearing of the tower from the camp. If anything is unclear, post a diagram, and we'll try to clarify.


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