B Hilbert's paradox of the Grand Hotel - An easier solution?

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Hilbert's paradox of the Grand Hotel illustrates how an infinite hotel can accommodate additional guests despite being full. One proposed solution suggests simply asking all current guests to step outside, allowing new arrivals to enter and choose from the infinite rooms. Critics argue this method lacks clarity on where existing guests should go and does not demonstrate the mathematical isomorphism between infinite sets. The traditional solution involves moving existing guests to rooms with doubled numbers, which effectively frees up space for newcomers. The discussion highlights the complexities of infinity and the differing perceptions of the paradox's resolution.
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Why the differen schemes of moving people around? When new people arrive, why not make everyone go outside, ande then make them all go in and pick a room. There should be infinite rooms for them to pick from, and everyone gets a room.
I know the paradox is about a hypotethical hotel with hypotethical guests, how else could new people arrive, when everyone (infinite) is already inside;) But maybe the ones outside are aliens, I don't know..
My real point though, is that there's no need for the intricate shuffeling of guests. When new guest arrive, just tell all the guest that are already in the hotel to step outside (or come to the lobby, I guess that's of infinite size too). Now you have an empty hotel with infinite rooms, and infinite people outside. Just tell them all to go inside and choose a room as there are infinite rooms to choose from. Does it need to be more complicated?
 
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Lars Krogh-Stea said:
Summary:: Why the differen schemes of moving people around? When new people arrive, why not make everyone go outside, ande then make them all go in and pick a room. There should be infinite rooms for them to pick from, and everyone gets a room.

I know the paradox is about a hypotethical hotel with hypotethical guests, how else could new people arrive, when everyone (infinite) is already inside;) But maybe the ones outside are aliens, I don't know..
My real point though, is that there's no need for the intricate shuffeling of guests. When new guest arrive, just tell all the guest that are already in the hotel to step outside (or come to the lobby, I guess that's of infinite size too). Now you have an empty hotel with infinite rooms, and infinite people outside. Just tell them all to go inside and choose a room as there are infinite rooms to choose from. Does it need to be more complicated?
What if it's raining outside?
 
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Lars Krogh-Stea said:
I know the paradox is about a hypotethical hotel with hypotethical guests, how else could new people arrive, when everyone (infinite) is already inside;) But maybe the ones outside are aliens, I don't know..
My real point though, is that there's no need for the intricate shuffeling of guests. When new guest arrive, just tell all the guest that are already in the hotel to step outside (or come to the lobby, I guess that's of infinite size too). Now you have an empty hotel with infinite rooms, and infinite people outside. Just tell them all to go inside and choose a room as there are infinite rooms to choose from. Does it need to be more complicated?
You're missing the whole point; namely, that even though there are currently an infinite number of people in the hotel's rooms when the new bunch (infinitely many) arrives, the scheme of asking the current guests to move to a room whose number is two times their old room number, clearly makes room for the new guests. An existing guest in room N is asked to go to room 2N. I don't see that as being an intricate shuffling.
A flaw in your method is that it doesn't specify where the existing guests are supposed to go, and where the new arrivals are supposed to go.

The underlying mathematics of Hilbert's Hotel is how one can tell that two infinite sets are the same size.
 
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Mark44 said:
You're missing the whole point; namely, that even though there are currently an infinite number of people in the hotel's rooms when the new bunch (infinitely many) arrives, the scheme of asking the current guests to move to a room whose number is two times their old room number, clearly makes room for the new guests. An existing guest in room N is asked to go to room 2N. I don't see that as being an intricate shuffling.
A flaw in your method is that it doesn't specify where the existing guests are supposed to go, and where the new arrivals are supposed to go.

The underlying mathematics of Hilbert's Hotel is how one can tell that two infinite sets are the same size.
I think you're missing my point.. It's hard to see why the groups of infinite people would be anything other than the same size, as any subset of an infinite number (however you shuffle the room, even if you use primes) will be infinite and therefore cardinally the same.
My point is that it's not a paradox. Which is proven by the easy solution i proposed. I mean why wouldn't a hotel with infinite rooms fit infinite people? Or, more precisely, why is it often presented as a riddle, with a complicated answer, when the "practical" (in the hypotethical sense) solution is extremely simple.

It's a bit like the Monty Hall problem, which really isn't a math problem. The math almost couldn't be simpler, it's the psychology of it that makes it hard.
 
Lars Krogh-Stea said:
Or, more precisely, why is it often presented as a riddle, with a complicated answer, when the "practical" (in the hypotethical sense) solution is extremely simple.
It's presented as a riddle because, perhaps, most people are not familiar with Cantor's theory of transfinite numbers. Don't forget that Cantor's work was controversial when he published:

https://en.wikipedia.org/wiki/Controversy_over_Cantor's_theory#Reception_of_the_argument

But, yes, the solution is simple to anyone with knowldege of modern set theory.
 
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Given Lars' post, I assume they do not realize if you brought a bus with one person for every real number in it, that those people could not fit in the hotel.
 
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Office_Shredder said:
Given Lars' post, I assume they do not realize if you brought a bus with one person for every real number in it, that those people could not fit in the hotel.
If you built a hotel with a room for every real number, what would you put on each door to identify the room?
 
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Office_Shredder said:
Given Lars' post, I assume they do not realize if you brought a bus with one person for every real number in it, that those people could not fit in the hotel.
What entity number would the pepople already in the the hotel have? I'm not sure that bus would be even hypothetically possible ;)
 
Infinity is not a number. It is a concept. The continuum hypothesis is a good example of how to think about infinite sets.
 
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  • #11
Lars Krogh-Stea said:
My point is that it's not a paradox. Which is proven by the easy solution i proposed. I mean why wouldn't a hotel with infinite rooms fit infinite people? Or, more precisely, why is it often presented as a riddle, with a complicated answer, when the "practical" (in the hypotethical sense) solution is extremely simple.
The paradox is that the hotel is full (each of the infinite number of rooms has someone in it), but we can still fit an infinite number of people into their own rooms. To people unfamiliar with transfinite numbers (which is probably the majority of people on earth), this is a paradox.

The "practical" solution is the usual one; namely where each existing guest moves from room N to room 2N. This scheme exhibits the isomorphism that demonstrates that the two sets--the set of positive integers and the set of even positive integers--have the same cardinality.

In the solution you described, it's impossible to say where a given guest has to move, so this scheme doesn't demonstrate the isomorphism between the two sets.
 
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  • #12
  • #13
Lars Krogh-Stea said:
My real point though, is that there's no need for the intricate shuffeling of guests. When new guest arrive, just tell all the guest that are already in the hotel to step outside (or come to the lobby, I guess that's of infinite size too). Now you have an empty hotel with infinite rooms, and infinite people outside. Just tell them all to go inside and choose a room as there are infinite rooms to choose from. Does it need to be more complicated?
That doesn't work, as whether you get everyone back into the hotel depends on how you organise things. For example, if we have an infinite number of women and men and we decide that the ladies should be accommodated first, then none of the men ever gets a room.
 
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  • #14
valenumr said:
Infinity is not a number. It is a concept. The continuum hypothesis is a good example of how to think about infinite sets.
I think the point here, is to separate countably infinite sets from uncountable sets. With uncountable sets, like the bus with a passenger for every real number, it wouldn't be possible (in my limiteted knowledge) to use a bijective function to map the passengers to the set of hotel rooms.
 
  • #15
valenumr said:
Fair enough, but at least algebraic numbers are somewhat concrete. The question is posed in terms of natural numbers.
Ugh that was bad phrasing. What maybe a better term would be "worldly". Most people grasp the concept.

Take for example transcendental numbers like pi or e. Does an integer exist with infinite numbers that actually equals one or the other if you move the decimal to the right place?
 
  • #16
PeroK said:
That doesn't work, as whether you get everyone back into the hotel depends on how you organise things. For example, if we have an infinite number of women and men and we decide that the ladies should be accommodated first, then none of the men ever gets a room.
I think that's included in the "hypothetical part". Or else the hotel wouldn't be full in the first place. It's like the paradox where you would never reach the door, because first you need to cover half the distance etc.. In the same way you just get up and walk over to the door, you just tell people to pick a room and they do ;)
 
  • #17
Mark44 said:
The paradox is that the hotel is full (each of the infinite number of rooms has someone in it), but we can still fit an infinite number of people into their own rooms. To people unfamiliar with transfinite numbers (which is probably the majority of people on earth), this is a paradox.

The "practical" solution is the usual one; namely where each existing guest moves from room N to room 2N. This scheme exhibits the isomorphism that demonstrates that the two sets--the set of positive integers and the set of even positive integers--have the same cardinality.

In the solution you described, it's impossible to say where a given guest has to move, so this scheme doesn't demonstrate the isomorphism between the two sets.
You could just move tenants up one room and add guests one at a time. If the hotel has infinite rooms, infinity plus one is still infinity.
 
  • #18
Lars Krogh-Stea said:
I think that's included in the "hypothetical part". Or else the hotel wouldn't be full in the first place. It's like the paradox where you would never reach the door, because first you need to cover half the distance etc.. In the same way you just get up and walk over to the door, you just tell people to pick a room and they do ;)
Can something with infinite capacity be full?
 
  • #19
valenumr said:
Can something with infinite capacity be full?
Seems like it can't :)
 
  • #20
Lars Krogh-Stea said:
I think that's included in the "hypothetical part". Or else the hotel wouldn't be full in the first place. It's like the paradox where you would never reach the door, because first you need to cover half the distance etc.. In the same way you just get up and walk over to the door, you just tell people to pick a room and they do ;)

It is still the case that if there was one person for every real number, this wouldn't work

The Zeno's paradox reveals a deep truth about the convergence of infinite sums, and the hotel is intended to reveal deep truths about infinity. Dismissing it as 100% trivial is only going to keep you from learning things
 
  • #21
Lars Krogh-Stea said:
Seems like it can't :)
Did you mean Cant(or)
 
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  • #22
valenumr said:
You could just move tenants up one room and add guests one at a time. If the hotel has infinite rooms, infinity plus one is still infinity.
Sure, but this would take an infinite amount of time, assuming some nonzero amount of time for the moves. If all the current guests move at the same time, then all the newcomers can take possession of the newly vacant rooms.
valenumr said:
Can something with infinite capacity be full?
Sure, if every room has a (current) guest in it.
Lars Krogh-Stea said:
Seems like it can't :)
See above.
 
  • #23
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Mark44 said:
Sure, but this would take an infinite amount of time, assuming some nonzero amount of time for the moves. If all the current guests move at the same time, then all the newcomers can take possession of the newly vacant rooms.

Sure, if every room has a (current) guest in it.

See above.
I'm not sure how time comes into play with the thought experiment. I hadn't thought about that previously.
 
  • #24
Mark44 said:
Sure, if every room has a (current) guest in it.
So is "every" even really defined on an infinite set?
 
  • #25
Mark44 said:
The paradox is that the hotel is full (each of the infinite number of rooms has someone in it), but we can still fit an infinite number of people into their own rooms. To people unfamiliar with transfinite numbers (which is probably the majority of people on earth), this is a paradox.

The "practical" solution is the usual one; namely where each existing guest moves from room N to room 2N. This scheme exhibits the isomorphism that demonstrates that the two sets--the set of positive integers and the set of even positive integers--have the same cardinality.

In the solution you described, it's impossible to say where a given guest has to move, so this scheme doesn't demonstrate the isomorphism between the two sets.
This, and PeroK's answer, is what i was after. I wanted to explore the common "riddle/paradox" vs the uncommon (for normal people like me) paradox that exists within a constrained hypothetical reality shaped to demonstrate a specific point about sets of numbers. My suspicion was that this was not a "riddle" as it was presented on TV in a quiz-like manner (where the point of the show is to deliver obscure knowledge in a humorous way, and no one is expected know the answer). I know wery little about numbers, but was intrigued by the presentation and read the wikipedia article. I do know psychology however, and had a feeling it was somewhat like the Monty Hall problem (but maybe reversed). I've seen people discuss the math involved in that problem for pages, not realizing that it's their biases and bult-in heuristics that keeps them from seeing the answer.
 
  • #26
valenumr said:
Did you mean Cant(or)
Cant(or) can't.. panini or punani. It's alle the same ;)
 
  • #27
Office_Shredder said:
It is still the case that if there was one person for every real number, this wouldn't work

The Zeno's paradox reveals a deep truth about the convergence of infinite sums, and the hotel is intended to reveal deep truths about infinity. Dismissing it as 100% trivial is only going to keep you from learning things
You are totally right. What i was trying to get across was that these kind of problems/paradoxes lose their aspect of teaching/reflection when they cross over from the experts, like you, to the public, like me. The hotel paradox is full of insights when presented to the academic audience, but is presented like a hard riddle when presented by common people to common people. Furthermore, my point was that, if all it was, was a riddle - then the soulution could be a simpler one. My example was to make them all go out and then enter again. All the academic value is lost in translation anyway. In the same way the Monty Hall problem is often presented like there exists an incomprehencible statistical solution that normal people won't understand, when in reality most people should understand it quite well if they would only let their guard down.
 
  • #28
valenumr said:
I'm not sure how time comes into play with the thought experiment. I hadn't thought about that previously.
Moving all of the current occupants to a room one number higher will take some finite, nonzero amount of time, so if you have to do this operation for an infinite number of new arrivals, it will take an infinite amount of time. The simpler way, moving each current occupant to the room number that is twice their previous room number, also takes a finite amount of time, but it happens only once.
valenumr said:
So is "every" even really defined on an infinite set?
Why not? Tell me a positive integer room number, and I'll tell you whether it has an occupant. Repeat until you get tired.
There is a trivial isomorphism between the set of current occupants and the set of positive integral hotel room numbers. Each person has a room, and each room has a person. That's what the statement "the hotel is full" means.
 
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  • #29
Lars Krogh-Stea said:
It's like the paradox where you would never reach the door, because first you need to cover half the distance etc.
That's essentially Zeno's Paradox, except in that one, it was about Achilles shooting an arrow. It was a paradox back when he came up with (500 BC?), but once you understand the concept of infinite series, it's no longer a paradox.

##\frac 1 2 + \frac 1 4 + \dots + \frac 1 {2^n} + \dots## is a convergent series that sums to 1. This is what Zeno didn't know.
 
  • #30
Mark44 said:
That's essentially Zeno's Paradox, except in that one, it was about Achilles shooting an arrow. It was a paradox back when he came up with (500 BC?), but once you understand the concept of infinite series, it's no longer a paradox.

##\frac 1 2 + \frac 1 4 + \dots + \frac 1 {2^n} + \dots## is a convergent series that sums to 1. This is what Zeno didn't know.
Unless you add quantum physics to the mix, then I might observe that, statistically, you've suddenly crossed the treshold :D Okay, I'm not making much sense. It's past bedtime in Norway.. Thanks for the lessons guys :)
 
  • #31
Lars Krogh-Stea said:
Unless you add quantum physics to the mix, then I might observe that, statistically, you've suddenly crossed the treshold :D Okay, I'm not making much sense.
No need for physics here, quantum or otherwise.
 
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  • #32
Mark44 said:
Moving all of the current occupants to a room one number higher will take some finite, nonzero amount of time, so if you have to do this operation for an infinite number of new arrivals, it will take an infinite amount of time. The simpler way, moving each current occupant to the room number that is twice their previous room number, also takes a finite amount of time, but it happens only once.

Why not? Tell me a positive integer room number, and I'll tell you whether it has an occupant. Repeat until you get tired.
There is a trivial isomorphism between the set of current occupants and the set of positive integral hotel room numbers. Each person has a room, and each room has a person. That's what the statement "the hotel is full" means.
I still don't see how time applies to the question. Its not really a ln element of the "paradox" as far as I can see.

But to the latter point, I would saying implying "each" to infinite sets is sketchy. It implies the rooms and guests are finitely enumerable. We can't really say infinity == infinity. What's the difference between 3*inf / inf vs. 100*inf / inf?
 
  • #33
Mark44 said:
Moving all of the current occupants to a room one number higher will take some finite, nonzero amount of time, so if you have to do this operation for an infinite number of new arrivals, it will take an infinite amount of time. The simpler way, moving each current occupant to the room number that is twice their previous room number, also takes a finite amount of time, but it happens only once.

Why not? Tell me a positive integer room number, and I'll tell you whether it has an occupant. Repeat until you get tired.
There is a trivial isomorphism between the set of current occupants and the set of positive integral hotel room numbers. Each person has a room, and each room has a person. That's what the statement "the hotel is full" means.
There is a trivial isomorphism of (R>=0, +) and (R, *). How is that relevant?
 
  • #34
valenumr said:
I'm not sure how time comes into play with the thought experiment. I hadn't thought about that previously.
Let's assume we have an empty hotel with a room for every positive integer and an ordered list of a countably infinite set of guests. If it takes one minute to accommodate each guest, then each guest gets their room sometime. The 60th guest gets their room after an hour; the 1440th guest after one day; and the millionth guest in less than two years.

Everyone on the list knows when they will get their room. Everyone gets a room eventually. Although, of course, there is never a time when everyone has a room!

Alternatively, the hotel has a process where they may accommodate the first guest in a minute, the next guest in 30 seconds, the next in 15 seconds, and they can continue getting faster and faster indefinitely. Now, everyone will be accommodated within 2 minutes.
 
  • #35
PeroK said:
Let's assume we have an empty hotel with a room for every positive integer and an ordered list of a countably infinite set of guests. If it takes one minute to accommodate each guest, then each guest gets their room sometime. The 60th guest gets their room after an hour; the 1440th guest after one day; and the millionth guest in less than two years.

Everyone on the list knows when they will get their room. Everyone gets a room eventually. Although, of course, there is never a time when everyone has a room!

Alternatively, the hotel has a process where they may accommodate the first guest in a minute, the next guest in 30 seconds, the next in 15 seconds, and they can continue getting faster and faster indefinitely. Now, everyone will be accommodated within 2 minutes.
I guess I've never seen the question formulated with time as a parameter. I always saw it as a comparison of infinities and nothing more. I'm not sure how much it changes things with constant time, I'll have to think about it. But in the immediate, I suppose it could be divergent timewise.
 
  • #36
valenumr said:
But to the latter point, I would saying implying "each" to infinite sets is sketchy. It implies the rooms and guests are finitely enumerable. We can't really say infinity == infinity. What's the difference between 3*inf / inf vs. 100*inf / inf?
This is not about normal addition. Infinity is not a real number subject to the laws of arithemtic. That's a critical point.

This is about mappings between infinite sets. And, that mappings between infinite sets are much more conceptually rich than mappings between finite sets.

For example, the set of positive even numbers is clearly a proper subset of the set of all positive integers. But, there exists a bijection (one-to-one and onto map) from one set to the other between them. In mathematical terms, two sets have the same cardinality if there exists a bijection between them. It's not the case that they must have different cardinality because one has a bijection to a proper subset of the other.

With finite sets it doesn't matter how you count. With infinite sets, you need to be more careful.

The example I gave was that if everyone is outside the hotel and they decide that the women should go in first, then it's clear that none of the men will ever get a room. As the infinite set of women will fill the hotel.

But, if we alternate between the sets of men and women, then everyone gets a room.
 
  • #37
PeroK said:
This is not about normal addition. Infinity is not a real number subject to the laws of arithemtic. That's a critical point.

This is about mappings between infinite sets. And, that mappings between infinite sets are much more conceptually rich than mappings between finite sets.

For example, the set of positive even numbers is clearly a proper subset of the set of all positive integers. But, there exists a bijection (one-to-one and onto map from one set to the other) between them. In mathematical terms, two sets have the same cardinality if there exists a bijection between them. It's not the case that they must have different cardinality because one has a bijection to a proper subset of the other.

With finite sets it doesn't matter how you count. With infinite sets, you need to be more careful.

The example I gave was that if everyone is outside the hotel and they decide that the women should go in first, then it's clear that none of the men will ever get a room. As the infinite set of women will fill the hotel.

But, if we alternate between the sets of men and women, then everyone gets a room.
I sort of? Get your gist, but it still shouldn't matter. You can apply your relation to the set of men and the set of women as well as to the rooms recursively.

On point, if we call men odd and women even, but only have even rooms, we can just multiply both groups by two, and still have enough rooms for all.
 
  • #38
valenumr said:
I sort of? Get your gist, but it still shouldn't matter.
It does matter. Not every 1-1 mapping between countable sets is onto. And not every onto mapping is 1-1.

If you're not careful you end up with two or more people to a room; or people with no room. Of course, you can always fix your process. But, the point is that not all processes work.

Unlike a finite hotel where you can ask the guests just to grab a room and it'll sort itself out.
 
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  • #39
valenumr said:
I sort of? Get your gist, but it still shouldn't matter. You can apply your relation to the set of men and the set of women as well as to the rooms recursively.

On point, if we call men odd and women even, but only have even rooms, we can just multiply both groups by two, and still have enough rooms for all.
Well, that's not exactly correct. 😡
 
  • #40
Yeah, my example totally put two people in every other room.
 
  • #41
valenumr said:
Yeah, my example totally put two people in every other room.
Oh, I should go sleep now. The analogy was just fine. 1 -> 2, 2 -> 4, 3 -> 6, etc, etc.
 
  • #42
Heres a link to a Youtube video that tries to explain how the hotel can become full when a bus with infinite number of people with names consisting of infinite combinations of the letters A.and B (uncountable).

How An Infinite Hotel Ran Out Of Room - Veritasium

At the point where he says to flip letters from the table diagonally, to make a name that is not in the list. Wouldn't that just be the next name on the list? An so on, infinitely? I feel it's like counting the first part of an countable infinity, and being interrupted by someone saying "Hey, you haven't said this (higher) number yet!"
Or is that exactly the point of an uncountable infinity, that you can always add to it. It seems you can also always add to a countable infinity? I mean, if you make a list of all countable numbers and flip single digits diagonally too..
 
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  • #43
Lars Krogh-Stea said:
Heres a link to a Youtube video that tries to explain how the hotel can become full when a bus with infinite number of people with names consisting of infinite combinations of the letters A.and B (uncountable).

How An Infinite Hotel Ran Out Of Room - Veritasium

At the point where he says to flip letters from the table diagonally, to make a name that is not in the list. Wouldn't that just be the next name on the list? An so on, infinitely? I feel it's like counting the first part of an countable infinity, and being interrupted by someone saying "Hey, you haven't said this (higher) number yet!"
Or is that exactly the point of an uncountable infinity, that you can always add to it. It seems you can also always add to a countable infinity? I mean, if you make a list of all countable numbers and flip single digits diagonally too..
The point is that if two sets have the same cardinality then there exists a bijection between them. The diagonal proof shows that if we assume a bijection, then we reach a contradiction in terms of a name that is not on the list. You can't turn round and say: let's use a different bijection where that name is on the list. If a bijection exists, then you can use it and stick to it.
 
  • #44
PeroK said:
If you built a hotel with a room for every real number, what would you put on each door to identify the room?
A scratch of an exact length.
 
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  • #45
valenumr said:
But to the latter point, I would saying implying "each" to infinite sets is sketchy. It implies the rooms and guests are finitely enumerable.
No, not sketchy. The rooms and guests are infinite in number, but they are countably infinite. I already demonstrated how to determine whether the hotel was full; i.e., each room as a guest in it, and each guest has a room.
valenumr said:
We can't really say infinity == infinity.
Right, and I am not doing this.
valenumr said:
What's the difference between 3*inf / inf vs. 100*inf / inf?
None, really, as both are not well defined.
valenumr said:
There is a trivial isomorphism of (R>=0, +) and (R, *). How is that relevant?
I have no idea what you're trying to say here.
 
  • #46
How I remember Hilbert's Hotel being presented is with these scenarios:
  • Hotel is full, and one new guest arrives. Solution: each current guest is asked to move from room N to room N+ 1, thus freeing room 1 for the new arrival.
  • Hotel is full, and M new guests arrive. Solution: each current guest is asked to move from room N to room N+ M, thus freeing rooms 1 through M for the new arrivals.
  • Hotel is full, and a bus with an infinite number (countably infinite) of passengers arrives. Solution: each current guest is asked to move from room N to room 2N, thus freeing rooms 1, 3, 5, etc. for the new arrivals.
 
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  • #47
Mark44 said:
How I remember Hilbert's Hotel being presented is with these scenarios:
  • Hotel is full, and one new guest arrives. Solution: each current guest is asked to move from room N to room N+ 1, thus freeing room 1 for the new arrival.
  • Hotel is full, and M new guests arrive. Solution: each current guest is asked to move from room N to room N+ M, thus freeing rooms 1 through M for the new arrivals.
  • Hotel is full, and a bus with an infinite number (countably infinite) of passengers arrives. Solution: each current guest is asked to move from room N to room 2N, thus freeing rooms 1, 3, 5, etc. for the new arrivals.
I follow you on these steps, but in the video from Veritasium they present a bus with infite number of people whose name is an infinite combination of the letter A and B. This is presented as an uncountably infinite group of people (trying to stay focused here..). Let's assume their names consisted of an infinite combination of the numbers 0 and 1 instead of A nd B. The buildup of that list would be exactly the same. Then let's use binary to count the rooms and put "digital" room numbers over the door. Doors would be named 00...000, 00...001, 00...010, 00...011, 00...100 and so on. I can't imagine a scenario where there is a person who can't find a hotel room where the number over the door matches his name. Surely the size of the hotel can not change, depending on what number system you use to count/name the rooms?
 
  • #48
Lars Krogh-Stea said:
I follow you on these steps, but in the video from Veritasium they present a bus with infite number of people whose name is an infinite combination of the letter A and B. This is presented as an uncountably infinite group of people (trying to stay focused here..). Let's assume their names consisted of an infinite combination of the numbers 0 and 1 instead of A nd B. The buildup of that list would be exactly the same. Then let's use binary to count the rooms and put "digital" room numbers over the door. Doors would be named 00...000, 00...001, 00...010, 00...011, 00...100 and so on. I can't imagine a scenario where there is a person who can't find a hotel room where the number over the door matches his name. Surely the size of the hotel can not change, depending on what number system you use to count/name the rooms?
We have had a lot of threads here started by people who disbelieve/don't understand the diagonal proof.

If you really want to debate the foundations of set theory and mathematical logic, then you should perhaps have started a new thread.

The diagonal proof has always seemed very simple to me. If you understand the basics of mathematical logic, there's not much to explain.

Note that for an infinite sequence, there is no last number. That's the definition of its being infinite. If there is a last digit, then (by definition) it's a finite sequence.
 
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  • #49
I haven't watched the video, but the distinction they're making is that it's impossible to get a 1-to-1, onto pairing (i.e., an isomorphism) between a countably infinite set (the hotel rooms) and an uncountably infinite set of new guests. This is the same as the difference between the set of positive integers and the set of real numbers in, say, the interval [0, 1].
 
  • #50
Mark44 said:
How I remember Hilbert's Hotel being presented is with these scenarios:
  • Hotel is full, and one new guest arrives. Solution: each current guest is asked to move from room N to room N+ 1, thus freeing room 1 for the new arrival.
  • Hotel is full, and M new guests arrive. Solution: each current guest is asked to move from room N to room N+ M, thus freeing rooms 1 through M for the new arrivals.
  • Hotel is full, and a bus with an infinite number (countably infinite) of passengers arrives. Solution: each current guest is asked to move from room N to room 2N, thus freeing rooms 1, 3, 5, etc. for the new arrivals.
Right. So is there any question that any of these cases are problem? Seems fine to me!
 
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