Hollow Cavity within a charged sphere

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SUMMARY

The discussion focuses on calculating the electric field within a hollow cavity located inside a uniformly charged sphere. Using Gauss' Law, the electric field at the surface of the sphere is determined to be p*R/3*e, where p represents charge density, R is the sphere's radius, and e is the electrical permittivity. The electric field inside the cavity, despite its absence of charge, is equivalent to the electric field outside the sphere, confirming that an electric field does exist within the cavity. This conclusion is critical for understanding electrostatics in charged bodies.

PREREQUISITES
  • Understanding of Gauss' Law in electrostatics
  • Familiarity with electric fields and charge density concepts
  • Knowledge of uniformly charged spheres and their properties
  • Basic grasp of electrical permittivity and its role in calculations
NEXT STEPS
  • Study the application of Gauss' Law in various geometries
  • Explore the concept of electric fields in non-uniform charge distributions
  • Investigate the implications of electric fields in cavities within charged conductors
  • Learn about the relationship between electric fields and potential energy in electrostatics
USEFUL FOR

This discussion is beneficial for physics students, electrical engineers, and anyone interested in advanced electrostatics and electric field calculations within charged materials.

Lancen
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Suppose I had a uniformly charged sphere of some density, inside this sphere at some position there is a cavity of some radius. If I wanted to then find the Electric field somewhere, like say the surface of the sphere, how would I approach the problem?

Heres what I did. I pretended the cavity didn't exist and using Gauss' Law found the electric field at the surface of the sphere to be p*R/3*e, where p is charge density, R is the radius of the sphere and e is the electrical permittivity. Then I found the electric field for the cavity which has a radius of R/2 and is located in such a way that the distance from its center to the surface of the charged sphere is 3/2*R. and that was 4.5*(p)*R/e. Thats where I am stuck. As I was doing this I thought I could treat this like those moment of inertia problems where you have a piece of a wheel or something missing and you just treat that piece as negative mass. But then when I went to do this, I realized all I would be doing if I subtracted the field off off the cavity would be adding a negative field. Also, if it is just a cavity is there even a field inside it?
 
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Yes, there will be an electric field inside the cavity. The electric field inside a cavity in a uniformly charged sphere is just the same as the electric field outside the sphere, and can be calculated using Gauss' Law.
 

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