Why Are Options B and C Incorrect for HOMO-LUMO Energy Gap?

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Discussion Overview

The discussion revolves around the HOMO-LUMO energy gap in relation to options B and C being incorrect. Participants explore the implications of this energy gap on the color of ionic compounds, particularly Group I ionic compounds, and seek clarification on the specific energy regions associated with these gaps.

Discussion Character

  • Exploratory, Conceptual clarification, Debate/contested

Main Points Raised

  • One participant asserts that as the energy difference between atomic orbitals increases, the interaction decreases, leading to a decrease in E and E*, suggesting that option A is correct.
  • Another participant states that ionic compounds will be colored if their HOMO-LUMO bandgap matches the energy of visible light, questioning the color of Group I ionic compounds.
  • A similar point is reiterated regarding Group I ionic compounds being generally colorless, implying their HOMO-LUMO band gap lies outside the visible region.
  • Participants inquire about the specific energy region of the HOMO-LUMO band gap for Group I ionic compounds, such as ultraviolet or infrared.
  • Two posts encourage self-exploration of the relationship between energy and frequency, referencing the equation E = hv.

Areas of Agreement / Disagreement

Participants express differing views on the implications of the HOMO-LUMO energy gap for ionic compounds, particularly regarding their color and the correctness of options B and C. The discussion remains unresolved regarding the specific energy regions of the HOMO-LUMO band gap.

Contextual Notes

There are unresolved assumptions regarding the definitions of color in relation to the HOMO-LUMO energy gap and the specific energy regions that may apply to Group I ionic compounds.

Amitkumarr
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Homework Statement
Which of the following statements is/are correct?

(a) The molecular orbitals are essentially identical to the relevant atomic orbitals at very high energy differences.

(b) Dominantly ionic compounds of group I have HOMO-LUMO energy gap in visible region generally.

(c) Coloured covalent diatomic molecules have HOMO-LUMO energy gap in ultraviolet region.

(d) All of the above.
Relevant Equations
No relevant equations.Based on Molecular orbital theory.
According to me Option A is a correct option because as the energy difference between two atomic orbitals increases,
their interaction, and thus the value of E (or E*) decreases. Here, E is the energy difference between the bonding molecular orbital and the atomic orbital of lower energy , while E* is the energy difference between the antibonding molecular orbital and the higher-energy atomic orbital. As these values decrease, the molecular orbitals become more and more similar to the atomic orbitals from which they are derived.
But what should be the correct answer for options B and C? The HOMO-LUMO energy gap of the given compounds lies in which region?
Note: Answer is given as option A.Why options B and C are wrong?
 

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Ionic compounds will be colored if the HOMO-LUMO bandgap is of the same energy as visible light. What does this mean to you? What color are Group I ionic compounds, generally? If that bandgap is of the same energy of a photon outside the visible region, will it be colored?
 
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chemisttree said:
Ionic compounds will be colored if the HOMO-LUMO bandgap is of the same energy as visible light. What does this mean to you? What color are Group I ionic compounds, generally? If that bandgap is of the same energy of a photon outside the visible region, will it be colored?
Group I ionic compounds are generally colorless so,their HOMO-LUMO band gap must lie outside the visible region.If that bandgap is of the same energy of a photon outside the visible region,they will not be colored,right?
Whereas,covalent diatomic molecules which are colored must have their HOMO-LUMO band gap in the visible region.

So,is there any specific region where the HOMO-LUMO band gap of Group I ionic compounds lie(like ultraviolet, infrared etc.)?
 
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chemisttree said:
That’s a good question. Try it for yourself!

Remember, E = hv
Thanks a lot for helping me and for giving me the link.
 

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