Horizontal/verticle distance, velocity

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SUMMARY

A water bomber at an altitude of 300 meters drops fire repellent while flying at a velocity of 60 m/s. The horizontal distance the load travels before hitting the fire can be calculated using the equations d = v(t) and t = √(2d/g), where g is the acceleration due to gravity (approximately 9.81 m/s²). The time of fall is determined to be 7.82 seconds, leading to a horizontal distance of 470 meters, or 0.47 kilometers. The error in the original calculation stemmed from incorrectly dividing by 60 instead of converting meters to kilometers by dividing by 1000.

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Homework Statement


At an altitude of 300 m, a water bomber drops a load of fire repellent on a hot spot of a forest fire. If the bomber is flying at a velocity of 60 m/s, what horizontal distance (km) does the load travel before hitting the fire?

Homework Equations


d=v(t), t=√(2d/2)


The Attempt at a Solution


i tried finding time using the formula i gave above which gave me 7.82 seconds. then i tried plugging that and 60m/s into d=vt then diving that answer by 60. ( to put it into km). what am i doing wrong?
 
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Why divide by 60? If you are converting from meters to kilometers, remember that there are 1000 meters in a kilometer...
 
o goodness. what a stupid mistake. thank u so much
 

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