How Are Quantum Numbers Derived from the Schrödinger Equation?

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SUMMARY

The derivation of quantum numbers from the Schrödinger Equation (S.E.) for bound systems results in the quantum numbers n, l, and m_l, each corresponding to specific wave functions and electrons. The fine structure arises from the inclusion of electron spin, specifically the spin states of 1/2 for electrons. In multi-electron atoms, the eigenstates are product states that account for the indistinguishability of electrons, meaning no two electrons can share the same set of quantum numbers. This discussion emphasizes the importance of treating electrons as fermions in multi-electron systems.

PREREQUISITES
  • Understanding of the Schrödinger Equation (S.E.)
  • Familiarity with quantum numbers (n, l, m_l)
  • Knowledge of electron spin and its implications
  • Concept of fermions and indistinguishability in quantum mechanics
NEXT STEPS
  • Study the derivation of quantum numbers from the Schrödinger Equation in detail
  • Explore the concept of fine structure in atomic physics
  • Learn about multi-electron atom configurations and their eigenstates
  • Investigate the implications of electron spin in quantum mechanics
USEFUL FOR

Students and professionals in quantum mechanics, physicists studying atomic structure, and anyone interested in the fundamental principles of quantum numbers and electron behavior in multi-electron systems.

jalalmalo
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let me see if I got this one right:

By solving the S E for bound system u got the quantum number n l and ml. each set of numbers corresponds to a curtain wave function and electron. One gots fine structure when adding the spin up 1/2 and down 1/2. so every electron in the atom has a set of these quantum numbers and no two electrons can have the same set.

thanx for your patience and replies
 
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jalalmalo said:
By solving the S E for bound system u got the quantum number n l and ml.
Yes, for V~1/r^2 at least.

jalalmalo said:
each set of numbers corresponds to a curtain wave function ...
Yes, in particular an eigenfunction of the Hamiltonian.

jalalmalo said:
... and electron.
I'm not sure. Actually, I don't think so. I haven't ever treated multi-electron atoms too rigorously, but I think that, strictly speaking, the eigenstates would be product states that combine all electrons as fermions, rather than treating them individually. Since electrons are identical, it doesn't make quantum sense to speak of individual electrons in a multi-electron system.

jalalmalo said:
One gots fine structure when adding the spin up 1/2 and down 1/2.
There is an energy splitting between the spin up and spin down states of a given orbital.

jalalmalo said:
so every electron in the atom has a set of these quantum numbers and no two electrons can have the same set.
Again, I think that the eigenstates of electrons in a multi-electron atom are actually products states, but I'm not sure.
 

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